我要四捨五入4列具有十進制值高達4位小數的csv文件

Question

我輸入

status,avgMeasuredTime,avgSpeed,extID,medianMeasuredTime,TIMESTAMP,vehicleCount,_id,REPORT_ID,Lat1,Long1,Lat2,Long2,Distance between 2 points,duration of measurements,ndt in kmh 
OK,74,50,668,74,1406859600,5,20746220,158324,56.23172069428216,10.104986076057457,56.23172069428216,56.22579478256016,1030,52,71 
OK,926,4,981,926,1412098500,0,28060227,210173,56.20913963031665,10.246642527612721,56.20913963031665,56.2026461982616,1106,88,45 

預期輸出：

status,avgMeasuredTime,avgSpeed,extID,medianMeasuredTime,TIMESTAMP,vehicleCount,_id,REPORT_ID,Lat1,Long1,Lat2,Long2,Distance between 2 points,duration of measurements,ndt in kmh 
OK,74,50,668,74,1406859600,5,20746220,158324,56.2317,10.1050,56.2317,56.2258,1030,52,71 
OK,926,4,981,926,1412098500,0,28060227,210173,56.2091,10.2466,56.2091,56.2026,1106,88,45 

正如你可以看到，我想四捨五入10日，11日，12日，13日。

請幫忙。提前致謝。

Answer 1

AWK方法：

awk 'BEGIN{FS=OFS=","}NR>1{for(i=NF-3;i>NF-7;i--) $i=sprintf("%.4f",$i)}1' file 

輸出：

status,avgMeasuredTime,avgSpeed,extID,medianMeasuredTime,TIMESTAMP,vehicleCount,_id,REPORT_ID,Lat1,Long1,Lat2,Long2,Distance between 2 points,duration of measurements,ndt in kmh 
OK,74,50,668,74,1406859600,5,20746220,158324,56.2317,10.1050,56.2317,56.2258,1030,52,71 
OK,926,4,981,926,1412098500,0,28060227,210173,56.2091,10.2466,56.2091,56.2026,1106,88,45 

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for(i=NF-3;i>NF-7;i--) - 通過在所述端

從第四場開始4個字段進行迭代

注：如果列數始終是靜態的，你可以通過它們的位置編號直接訪問它們：

awk 'BEGIN{FS=OFS=","}NR>1{for(i=10;i<=13;i++) $i=sprintf("%.4f",$i)}1' file 

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如果你想的Python方法 - 在這裏我們去：

with open("yourfile", 'r') as f: 
    for k,l in enumerate(f.read().splitlines()): 
     if k > 0: 
      items = l.split(',') 
      items[-4:-8:-1] = ["%.4f" % float(i) for i in items[-4:-8:-1]] 
      l = ','.join(items) 
     print(l) 

輸出將是相同的