START WITH和甲骨文CONNECT BY SQL

賬戶

CUSTOMER_ID PAYING_ACCOUNT_ID PARENT_ACCOUNT_ID  ACCOUNT_ID COMPANY_ID 
24669   24669    24669     24669  0 
24671   24671    24669     24671  0 
24670   24670    24669     24670  0 
3385217  3385217    24670     3385217  0 
158   158     158     158   0 
159   159     158     159   0 
160   160     159     160   0 
161   161     160     161   0 
162   162     160     162   0 
180   180     180     180   0

這是DDL

CREATE TABLE "SYSTEM"."ACCOUNT" 
("CUSTOMER_ID"  NUMBER(20,0) NOT NULL ENABLE, 
"PAYING_ACCOUNT_ID" NUMBER(20,0), 
"PARENT_ACCOUNT_ID" NUMBER(20,0), 
"ACCOUNT_ID"  NUMBER, 
"COMPANY_ID"  NUMBER)

這是我的查詢

select lpad(' ', 2*level) || A.ACCOUNT_ID AS LEVEL_LABEL, 
      LEVEL, 
      A.* 
     from ACCOUNT A 
start with PARENT_ACCOUNT_ID IN 
         (select PARENT_ACCOUNT_ID 
          from ACCOUNT 
         where ACCOUNT_ID IN 
             (select PARENT_ACCOUNT_ID 
              from ACCOUNT 
              where parent_account_id != account_id) 
              and ACCOUNT_ID = PARENT_ACCOUNT_ID) 
    CONNECT BY NOCYCLE PRIOR A.ACCOUNT_ID = A.PARENT_ACCOUNT_ID;

查詢的主要目的是選擇具有層次關係的數據，即PARENT_ACCOUNT_ID & ACCOUNT_ID，但是我得到了查詢返回的重複數據。

任何建議非常感謝。由於

來源

2012-02-13 user871695

parent_account_id和account_id如何在同一時間（最內在的查詢）不同和相等？這可能不是您的原始查詢，因爲它應該產生完全爲0的結果，因此根本沒有重複。 – Benoit 2012-02-13 09:25:06

爲什麼不乾脆：

SELECT level, * FROM accounts 
START WITH parent_account_id = account_id 
CONNECT BY PRIOR account_id = parent_account_id 
     AND account_id <> parent_account_id

？

來源

2012-02-13 09:14:29 Benoit

感謝您的建議。 – user871695 2012-02-13 09:23:56

@ user871695這個答案能工作嗎？ – cctan 2012-02-13 09:27:25

是的，它工作:) – user871695 2012-02-14 03:19:18

您可以使用pl/sql HOST命令來調用.exe文件。

來源

2017-08-28 06:12:19

START WITH和甲骨文CONNECT BY SQL

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