顯示基於加入ID的兩個不同colums中的值

Question

我試圖按照標題爲SQL Server創建select語句。 我的數據是：

ID | JoiningID | Value | 

1 | 1 | 10 

2 | 1 | 11 

3 | 2 | 10 

4 | 2 | 10 

5 | 3 | 15 

6 | 3 | 9 

我試圖輸出三列這將是這樣的：

JoiningID | Column1值| Column2值

1 | 10 | 11 

2 | 10 | 10 

3 | 15 | 9 

條件是它需要在select語句內而不是在where語句中。

謝謝你的時間。

Answer 1

您可以枚舉值，然後使用pivot或有條件聚集：

select joiningid, 
     max(case when seqnum = 1 then value end) as value1, 
     max(case when seqnum = 2 then value end) as value2 
from (select t.*, row_number() over (partition by joiningid order by id) as seqnum 
     from t 
    ) t 
group by joiningid; 

Answer 2

你可以簡單地做..

SELECT * FROM TABLE1 
WHERE JoiningID IN(SELECT JoiningID from TABLE2) 

或..

SELECT * FROM TABLE1 
WHERE JoiningID NOT IN(SELECT JoiningID from TABLE2) 

或者，你可以做JOIN或LEFT JOIN ..