消息1倍以上

Question

class SomeUI  
{ 
SocketMessageSender messageSender; 
// ensure that its initialized ... 
private void bSendMessageActionPerformed(java.awt.event.ActionEvent evt) { 
     try { 
      // TODO add your handling code here: 
      messageSender.sendMessage(jMessage.getText()); 
      jMessage.setText(""); 
     } catch (IOException ex) { 
      Logger.getLogger(TeKServer.class.getName()).log(Level.SEVERE, null, ex); 
     } 
    } 
} 

ERROR：在線程異常 「AWT-EventQueue的-0」 了java.lang.RuntimeException：不可編譯的源代碼 - 錯誤的符號類型：bSendMessageActionPerformed

Answer 1

爲什麼你不斷打開插座，並關閉它每按一下按鈕。創建一個類，只要應用程序運行，就可以讓套接字保持打開狀態。套接字連接可以做到當應用程序starts.You可以嘗試下面的類

public class SocketMessageSender 
{ 
    private String host; 
    private int port; 
    private DataOutputStream dos; 

    public SocketMessageSender(String host, int port) 
    { 
     this.host = host; 
     this.port = port; 
    } 

    // call when application starts 
    public void initConnection() throws IOException 
    { 
     InetAddress address = InetAddress.getByName(host); 
     Socket connection = new Socket(address, port); 
     dos = new DataOutputStream(connection.getOutputStream()); 
    } 

    //call from button click 
    public void sendMessage(String message) throws IOException 
    { 
     if(dos != null) 
     { 
      dos.writeUTF(message); 
      dos.flush(); 
     } 
    } 

    // call when application exits 
    public void closeConnection() throws IOException 
    { 
     if(dos!= null) 
     { 
      dos.close(); 
     } 
    } 
} 

希望它可以幫助...

假設你有一個像

class SomeUI 
{ 
    SocketMessageSender messageSender; 
    // ensure that its initialized ... 



private void bSendMessageActionPerformed(java.awt.event.ActionEvent evt) { 
    messageSender.sendMessage(jMessage.getText()); 
    jMessage.setText(""); 
} 
} 

我覺得一個類該類簽名應該是這樣的...

public class MyPanel extends JPanel implements ActionListener 
{ 
    private SocketMessageSender messageSender; 
    private Message jMessage = new Message();// This is just a temp class, replace this with your class 

    public MyPanel() 
    { 
     messageSender = new SocketMessageSender("some host", 8080); 
     try 
     { 
      messageSender.initConnection(); 
     } 
     catch(IOException e) 
     { 
      Logger.getLogger(MyPanel.class.getName()).log(Level.SEVERE, null, e); 
     } 
    } 

    @Override 
    public void actionPerformed(ActionEvent e) 
    { 
     try { 
      // TODO add your handling code here: 
      messageSender.sendMessage(jMessage.getText()); 
      jMessage.setText(""); 
     } catch (IOException ex) { 
      Logger.getLogger(MyPanel.class.getName()).log(Level.SEVERE, null, ex); 
     } 
    } 
} 

Answer 2

考慮使用ObjectOutputStream/ObjectInputStream的並通過套接字寫入對象。 java2s.com上有很多示例

請注意，如果您多次編寫同一對象，則需要在寫入之前重置（）流，然後刷新它。