反話（而不是字母）的字符串，而無需使用.reverse（）

Question

我的工作問題詢問我寫一個函數reverseMessage()接受一個字符串消息，並反轉到位單詞的順序。

我第一次來到了作品，但顯然不符合這一任務的requirements答案：

function reverseMessage(string) { 
    return string.split(" ").reverse().join(" "); 
} 

例如：

var string = "reversed are string your in words the now" 
var results = "now the words in your string are reversed" 

新的解決方案：

我會想通過該數組此字符串分割成一個數組，然後循環，並與最後一個索引，與第二到最後一個索引，與3第三索引的第二索引交換第一索引rd到最後的索引等...直到我在中間相遇。

我試圖讓下面的工作兩種不同的功能：在正確的軌道上

function reverseMessage(string) { 
    var array = string.split(" "); 
    //loop through array and replace first index with last index, second 
    index with second to last index, third index with third to last index, etc 
    for (var i = 0; i < array.length/2; i++) { 
     for (var j = (array.length-1); j > array.length/2; j--) { 
      array[i] = array[j]; 
      array[j] = array[i]; 
      messageSplit.join(","); 
    } 
}; 



function reverseMessage2(string) { 
    var array = string.split(" "); 
    var newArray = [] 
    for (var i = 0; i < array.length/2; i++) { 
     newArray.unshift(array[i]++); 
     newArray.join(","); 
     return newArray; 
    } 
}; 

我是誰？

Answer 1

所以在你reverseMessage功能正在嘗試換爲變量，你正在做

陣列[i] =陣列[J]。 array [j] = array [i];

這是給陣列[我] =陣列[J]所以讓說數組[I] =「這」和陣列[J] =「那」根據你的代碼陣列[我]將是「那」與陣列[J]也將是「那」所以你可以嘗試這樣的事：

function reverseMessage(string) { 
    var array = string.split(" "); 
    //loop through array and replace first index with last index, second 
    //index with second to last index, third index with third to last index, etc 
    for (var i = 0,j=(array.length)-1; i < array.length/2; i++) { 
      temp=array[i] 
      array[i] = array[j]; 
      array[j]=array[i] 
      array[j] = temp; j--;} 
     console.log(array.join(" ")); 
}; reverseMessage("find you will pain only go you recordings security the into if"); 

Answer 2

function reverseMessage(string) { 
    var array = string.split(" "); 
    var result=""; 
    for (var i = array.length-1; i >=0; i--) { 
     result+=array[i]+" "; 
    } 
    console.log(result); 
}; 

Answer 3

試試這個

function reverseMessage(str) { 

    var arrStr = []; 
    var temp =""; 
    for(var i = 0 ; i < str.length ; i++) 
    { 
     if(str[i] === " ") 
     { 
      arrStr.push(temp); 
      temp=""; 
     } 
     else 
     { 
      temp += str[i]; 
     } 
    } 
    if(temp.length >= 0) 
    { 
     arrStr.push(temp); 
    } 
    var result = ""; 
    for(var x=arrStr.length-1 ; x >=0 ; x--) 
    { 
     result += " "+arrStr[x]; 
    } 
    return result; 
} 


console.log(reverseMessage("I am here")); 

Answer 4

你想要做的是分裂的話消息到各個琴絃顛倒它們，然後把它們相加，這將扭轉什麼他們到位。嘗試

function reverseMessage(message){ 
    var reversedMessage = ''; //A string to hold the reversed message 
    var words = message.split(' '); 
    for(var i =0; i< words.length; i++){ 
    reversedMessage += reverse(words[i]) + " ";// add the reversed word to the reversed message, with a space at the end so the words dont touch 
    } 
    return reversedMessage 
} 
//A helper function that reverses a string 
function reverse(s) { 
    var o = ''; 
    for (var i = s.length - 1; i >= 0; i--) 
    o += s[i]; 
    return o; 
} 

來源：http://eddmann.com/posts/ten-ways-to-reverse-a-string-in-javascript/

Answer 5

好，別人的你必須這樣做：

function rev(s){ 
 
    var a = s.split(/ /), 
 
     l = a.length; 
 
     i = l/2 | 0; 
 
    while (i--) a.splice(i, 1, a.splice(l-1-i, 1, a[i])[0]); 
 
    return a.join(' '); 
 
} 
 

 
    document.write(rev('0 1 2 3 4 5 6 7 8 9'));

Answer 6

使用Array.split()，Array.pop()，Array.push()和String.substr()：

var flip = function(str) { 
 
    var res = "", sp = " ", arr = str.split(sp); 
 
    while (arr.length) 
 
    res += arr.pop() + sp; 
 
    return res.substr(0, res.length - 1); //remove last space 
 
}; 
 
alert(flip("reversed are string your in words the now"));

使用String.lastIndexOf()和String.substr()：

var flip = function(str) { 
 
    var res = "", i, sp = ' '; 
 
    while (str) { 
 
    i = str.lastIndexOf(sp); 
 
    res += str.substr(i + 1) + sp; 
 
    str = str.substr(0, i); 
 
    } 
 
    return res.substr(0, res.length - 1); //remove last space 
 
}; 
 

 
alert(flip("reversed are string your in words the now"));

Answer 7

with `pop()` ;) 

function reverseMessage(string) { 
     var array = string.split(" "); 
     var result=""; 
     while (array.length > 0) { 
      result += array.pop()+" "; 
     } 
     console.log(result); 
    };