比較兩列，並在THRID

Question

返回的結果可以說我有這個表：

-------------------------------------------------------------------------- 
| id | allowed_to_play_pokemon_go_after | last_played_pokemon_go | name | 
-------------------------------------------------------------------------- 
| 1 |      20-JUL-16 |    19-JUL-16 | Jhon | 
-------------------------------------------------------------------------- 
| 2 |      19-JUL-16 |    21-JUL-16 | Bill | 
-------------------------------------------------------------------------- 

現在我想要做一個選擇這樣的：

SELECT name, (last_played_pokemon_go > allowed_to_play_pokemon_go_after) as must_punish 
FROM myTable; 

其中「must_punish」有bo布爾值（1/0）。

Answer 1

您可以使用case：

SELECT name, 
     (case when last_played_pokemon_go > allowed_to_play_pokemon_go_after then 1 else 0 
     end) as must_punish 
FROM myTable; 

甲骨文（數據庫）不具有布爾數據類型。一個數字應該沒問題。