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所以我爲我的類創建了一個gpa計算器。 一切似乎看起來很好,似乎它會正常工作,但由於一些奇怪的原因,當我嘗試運行它時,我得到這些錯誤。 什麼導致他們? 它真讓人沮喪。Java在stringinput上拋出異常
Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Scanner.java:864)
at java.util.Scanner.next(Scanner.java:1485)
at java.util.Scanner.nextDouble(Scanner.java:2413)
at GpaCalculator.main(GpaCalculator.java:22)
的源代碼:
import java.util.*;
public class GpaCalculator {
public static void main(String[] args) {
Scanner numberinput = new Scanner(System.in);
Scanner stringinput = new Scanner(System.in);
// this program will calculate the gpa of four classes
double A,B,C,D,F;
double grade,grade2,grade3,grade4;
double gpa = 0,name,Course2,Course3,Course4;
int Course1;
A = 4.0;
B = 3.0;
C = 2.0;
D = 1.0;
F = 0.0;
System.out.println("Please enter your name>>>");
name = stringinput.nextDouble();
System.out.println("Please enter your course>>>");
Course1 = stringinput.nextInt();
System.out.println("What is the weight of this class? Normal, Honors, or AP?>>>");
String weight = stringinput.nextLine();
System.out.println("What is your grade in the class?>>>");
grade = numberinput.nextDouble();
if (weight.equalsIgnoreCase("honors"))
gpa = gpa + 1;
else if (weight.equalsIgnoreCase("Ap"))
gpa = gpa + 1.5;
else if (weight.equalsIgnoreCase("normal"));
if (grade >= 100)
grade = A;
else if (grade >= 91)
grade = B;
else if (grade >= 83)
grade = C;
else if (grade >= 75)
grade = D;
else if (grade >= 67)
grade = F;
System.out.println("Please enter your course>>>");
Course2 = stringinput.nextDouble();
System.out.println("What is the weight of this class? Normal, Honors, or AP?>>>");
String weight2 = stringinput.nextLine();
System.out.println("What is your grade in the class?>>>");
grade2 = numberinput.nextDouble();
if (weight2.equalsIgnoreCase("honors"))
gpa = gpa + 1;
else if (weight2.equalsIgnoreCase("Ap"))
gpa = gpa + 1.5;
else if (weight2.equalsIgnoreCase("normal"));
if (grade2 >= 100)
System.out.println(A);
else if (grade2 >= 91)
System.out.println(B);
else if (grade2 >= 83)
System.out.println(C);
else if (grade2 >= 75)
System.out.println(D);
else if (grade2 >= 67)
System.out.println(F);
System.out.println("Please enter your course>>>");
Course3 = stringinput.nextDouble();
System.out.println("What is the weight of this class? Normal, Honors, or AP?>>>");
String weight3 = stringinput.nextLine();
System.out.println("What is your grade in the class?>>>");
grade3 = numberinput.nextDouble();
if (weight3.equalsIgnoreCase("honors"))
gpa = gpa + 1;
else if (weight3.equalsIgnoreCase("Ap"))
gpa = gpa + 1.5;
else if (weight3.equalsIgnoreCase("normal"));
if (grade3 >= 100)
System.out.println(A);
else if (grade3 >= 91)
System.out.println(B);
else if (grade3 >= 83)
System.out.println(C);
else if (grade3 >= 75)
System.out.println(D);
else if (grade3 >= 67)
System.out.println(F);
System.out.println("Please enter your course>>>");
Course4 = stringinput.nextDouble();
System.out.println("What is the weight of this class? Normal, Honors, or AP?>>>");
String weight4 = stringinput.nextLine();
System.out.println("What is your grade in the class?>>>");
grade4 = numberinput.nextDouble();
if (weight4.equalsIgnoreCase("honors"))
gpa = gpa + 1;
else if (weight4.equalsIgnoreCase("Ap"))
gpa = gpa + 1.5;
else if (weight4.equalsIgnoreCase("normal"));
if (grade4 >= 100)
System.out.println(A);
else if (grade4 >= 91)
System.out.println(B);
else if (grade4 >= 83)
System.out.println(C);
else if (grade4 >= 75)
System.out.println(D);
else if (grade4 >= 67)
System.out.println(F);
gpa = grade + grade2 + grade3 + grade4/4;
System.out.println(name);
System.out.println(Course1 + ": " + grade);
System.out.println(Course2 + ":" + grade2);
System.out.println(Course3 + ": " + grade3);
System.out.println(Course4 + ":" + grade4);
System.out.println(gpa);
}
}
等等,你的名字是雙?你爲什麼使用'stringinput.nextDouble'作爲名字?不要創建多個掃描器,只需使用一個來檢測輸入... – Li357
舊的「我有一個異常,但我不能使用它提供的信息來調試我自己的代碼」。我應該猜到了...... – John3136
那麼我該如何解決例外問題,它不會在問題標籤中顯示任何問題 –