PHP繼續獲得循環中的休息價值

Question

我有一些JSON數據，我想匹配一些條件後重新安裝它。

$mm='a'; 
$nn='104'; 

$jn=array(); 
$j2='[ 
{"a":"c","n":"103","t":"rfg"}, 
{"a":"a","n":"104","t":"bmf"},// <- find the data, re-install from the next line 
{"a":"b","n":"105","t":"tit"}, 
{"a":"a","n":"106","t":"iou"}, 
{"a":"b","n":"107","t":"wdf"} 
]'; 
$t2=json_decode($j2); 

foreach($t2 as $d2){ 
    if($mm==$d2->a&&$nn==$d2->n){ 
     continue; 
    } 
    $jn['a']=$d2->a; 
    $jn['n']=$d2->n; 
    $jn['t']=$d2->t; 
    $p.=json_encode($jn).','; 
} 

echo '['.substr($p,0,-1).']'; 

我只需要找到比賽後返回JSON數據[{"a":"b","n":"105","t":"tit"},{"a":"a","n":"106","t":"iou"},{"a":"b","n":"107","t":"wdf"}]

Answer 1

下面的代碼將做的工作 追加的字符串。

$mm='a'; 
$nn='104'; 
$jn=array(); 
$j2='[{"a":"c","n":"103","t":"rfg"},{"a":"a","n":"104","t":"bmf"},{"a":"b","n":"105","t":"tit"},{"a":"a","n":"106","t":"iou"},{"a":"b","n":"107","t":"wdf"}]'; 
$t2=json_decode($j2); 
//echo "<pre>"; 
//print_r($t2); 
//exit(); 
$append = false; 
$p=''; 
foreach($t2 as $key=>$d2){ 

    $jn['a']=$d2->a; 
    $jn['n']=$d2->n; 
    $jn['t']=$d2->t; 
    if($append){  
     $p.=json_encode($jn).','; 
    } 
    if($mm==$d2->a&&$nn==$d2->n){ 
     $append=true; 
    } 
} 

echo '['.substr($p,0,-1).']'; 

Answer 2

我希望你明白這一點。

<?php 
$mm='a'; 
$nn='104'; 

$jn=array(); 
$j2='[ 
{"a":"c","n":"103","t":"rfg"}, 
{"a":"a","n":"104","t":"bmf"},// <- find the data, re-install from the next line 
{"a":"b","n":"105","t":"tit"}, 
{"a":"a","n":"106","t":"iou"}, 
{"a":"b","n":"107","t":"wdf"} 
]'; 
$t2=json_decode($j2); 

$i=0; 
foreach($t2 as $d2) 
{ 
    if($mm==$d2->a && $nn==$d2->n) 
    { 
     $jn['a']=$d2->a; 
     $jn['n']=$d2->n; 
     $jn['t']=$d2->t; 
     if($i==1) 
     { 
      $p=json_encode($jn).','; 
     } 
     else 
     { 
      $p.=json_encode($jn).','; 
     } 
    } 
    $i++; 
} 

echo '['.substr($p,0,-1).']';