如何創建這個複雜的查詢？

Question

我有3個表格：項目，技能和project_skills。在項目表中，我持有項目的一般數據。第二個表技能我擁有技能ID和技能名稱我也有project_skills表是持有項目的技能關係。下面是表的方案：

CREATE TABLE IF NOT EXISTS `project_skills` (
    `project_id` int(11) NOT NULL, 
    `skill_id` int(11) NOT NULL, 
    KEY `project_id` (`project_id`), 
    KEY `skill_id` (`skill_id`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_turkish_ci; 


CREATE TABLE IF NOT EXISTS `projects` (
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `employer_id` int(11) NOT NULL, 
    `project_title` varchar(100) COLLATE utf8_turkish_ci NOT NULL, 
    `project_description` text COLLATE utf8_turkish_ci NOT NULL, 
    `project_budget` int(11) NOT NULL, 
    `project_allowedtime` int(11) NOT NULL, 
    `project_deadline` datetime NOT NULL, 
    `total_bids` int(11) NOT NULL, 
    `average_bid` int(11) NOT NULL, 
    `created` datetime NOT NULL, 
    `active` tinyint(1) NOT NULL, 
    PRIMARY KEY (`id`), 
    KEY `created` (`created`), 
    KEY `employer_id` (`employer_id`), 
    KEY `active` (`active`), 
    FULLTEXT KEY `project_title` (`project_title`,`project_description`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_turkish_ci AUTO_INCREMENT=3 ; 

CREATE TABLE IF NOT EXISTS `skills` (
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `category` int(11) NOT NULL, 
    `name` varchar(100) COLLATE utf8_turkish_ci NOT NULL, 
    `seo_name` varchar(100) COLLATE utf8_turkish_ci NOT NULL, 
    `total_projects` int(11) NOT NULL, 
    PRIMARY KEY (`id`), 
    KEY `seo_name` (`seo_name`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_turkish_ci AUTO_INCREMENT=224 ; 

我要選擇具有相關技能的名字項目。我想我必須使用JOIN，但我不知道該怎麼辦。由於

Answer 1

這聽起來像一個JOIN是完全正確的：

SELECT ... 
FROM projects 
INNER JOIN project_skills ON (project_skills.project_id = projects.id) 
INNER JOIN skills ON (skills.id = project_skills.skill_id) 

Answer 2

select * from projects 
left join project_skills on projects.id = project_skills.project_id 
left join skills on project_skills.skills_id = skills .id 

記：你並不需要所有列，但是這將讓你看到是怎麼回事，你選擇你所需要的列前。