我從數據庫中檢索一個LatLng座標字符串,並使用PHP的爆炸函數並將其存儲在數組中。我想將數組從PHP傳遞到JavaScript。此外,我希望多邊形函數接受數組並相應地繪製座標。我目前很難過。 :(請幫助LatLng作爲Google Maps API中的分解陣列
<script type="text/javascript"
src="https://maps.googleapis.com/maps/api/js?key=AIzZfro&sensor=false">
</script>
<script>
function initialize() {
var myLatLng = new google.maps.LatLng(8.5000,125.8333);
var myOptions = {
zoom: 8,
center: myLatLng,
};
var map = new google.maps.Map(document.getElementById("map-canvas"),
myOptions);
var davaoCoordinates = [
new google.maps.LatLng(7.0644,125.6078),
new google.maps.LatLng(8.4833,124.6500),
new google.maps.LatLng(8.5000,125.8333)
];
var davaoCity = new google.maps.Polygon({
path: davaoCoordinates,
strokeColor: "#FF0000",
strokeOpacity: 1.0,
strokeWeight: 2
});
davaoCity.setMap(map);
}
google.maps.event.addDomListener(window, 'load', initialize);
</script>
這裏是PHP代碼:
<?php
$connect = mysql_connect("localhost", "root", "");
mysql_select_db('capdb');
if (mysqli_connect_errno()){
echo "Failed to connect to database: " . mysqli_connect_error();
}
$query ="SELECT cap_info.event, cap_info.sendername, cap_info.urgency, cap_area.polygon
FROM cap_info
INNER JOIN cap_area ON cap_info.capid = cap_area.capid
WHERE cap_info.capid =1";
$result = mysql_query($query);
if (!$result){
echo "Query Error." . mysql_error();
exit;
}
if (mysql_num_rows($result) == 0){
echo "No rows found, nothing to print.";
exit;
}
while ($row = mysql_fetch_array($result)){
$event = $row['event'];
$sender = $row['sendername'];
$urgency = $row['urgency'];
$polygon = $row['polygon']."\n";
}
$coordsArray = explode (" ", $polygon);
$count = sizeof($coordsArray);
//$n=0;
//while ($n < $count){
//echo $coordsArray[$n];
//$n++;
//}
?>
一個提示:不要使用mysql_connect http://php.net/function.mysql-connect如果你想JavaScript加載一堆座標,那麼你的PHP可以返回JSON。只需使用json_encode返回它http://www.php.net/json_encode。如果你只想在頁面加載時創建點,那麼mjayt應該爲你工作。 – HMR