Question

我有2個字符串是這樣的：

$post_des = 'Neque porro quisquam est qui do <a href = "http://example.com/lorem_ipsum"> lorem ipsum </a> quia dolor sit amet, consectetur, adipisci velit...'; 

$post_detail = '<a href = "http://example.com/lorem_ipsum">lorem ipsum </a> dolor sit amet, consectetur adipiscing elit. Donec quis purus finibus, ultricies diam at, faucibus nunc. Donec ac luctus ipsum,vitae <a href = "http://example.com/vehicula"> vehicula </a> erat. ' ; 

，並希望刪除所有重複AHREF標籤，就像這樣：

$post_des = 'Neque porro quisquam est qui do <a href = "http://example.com/lorem_ipsum"> lorem ipsum </a> quia dolor sit amet, consectetur, adipisci velit...'; 

$post_detail = 'lorem ipsum dolor sit amet, consectetur adipiscing elit. Donec quis purus finibus, ultricies diam at, faucibus nunc. Donec ac luctus ipsum,vitae <a href = "http://example.com/vehicula"> vehicula </a> erat. ' ; 

我試圖用DOM文檔和in_array，但還有約2百萬個標籤（ex lorem ipsum，vehicular）。有沒有更簡單的方法？

Answer 1

使用preg_match獲取所有鏈接標記出現並迭代它們以刪除（替換爲空字符串）$ post_detail。 [小提琴] [1]

if(preg_match('/<a.*\>/',$post_des,$link_tags)) 
{ 
    foreach($link_tags as $link_tag) 
    { 
     preg_match('#<a[^>]+>(.+?)</a>#ims', $link_tag,$str); 

     $post_detail = str_replace($link_tag,@$str[1],$post_detail); 
    } 
} 

http://viper-7.com/Ul8BBN