我有4個oracle SQL查詢，我想要在一個結果

Question

這4個查詢產生所需的結果，但我想把這些查詢包裝成一個查詢，返回每個查詢作爲水平列與垂直相應的查詢結果。

我有限的所有查詢到ROWNUM < = 20

SELECT * FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (1/24)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) WHERE 
rownum <= 20; 

SELECT * FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (1)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) WHERE 
rownum <= 20; 

SELECT * FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (7)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) WHERE 
rownum <= 20; 

SELECT * FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (30)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) WHERE 
rownum <= 20; 

人對如何做到這一點有什麼建議？

編輯：我想指定我不希望結果在彼此之上。不同的查詢必須是水平列，而他們各自的結果去vertically.a

Answer 1

通過他們的rownum加入他們的行列（記得別名ROWNUM）

select * from 
(
SELECT rownum rownr, a.* FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (1/24)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) a WHERE 
rownum <= 20 
) a, 
(
SELECT rownum rownr, b.* FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (1)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) b WHERE 
rownum <= 20 
) b, 
(
SELECT rownum rownr, c.* FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (7)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) c WHERE 
rownum <= 20 
) c, 
(
SELECT rownum rownr, d.* FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (30)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) d WHERE 
rownum <= 20 
) d 
where a.rownr = b.rownr 
and a.rownr = c.rownr 
and a.rownr = d.rownr