將使用IIF的訪問查詢轉換爲SQL Server

Question

我正在尋找一些幫助將訪問查詢轉換爲sql服務器。

它的大部分我罰款，但我與IIF部分

SELECT * 
FROM (([if_submission] 
    LEFT JOIN [payrollruns] 
      ON [if_submission].[periodnumber] = [payrollruns].[runid]) 
    LEFT JOIN [if_rti_finalfps_q] 
      ON [payrollruns].[runid] = [if_rti_finalfps_q].[runid]) 
    LEFT JOIN [if_rti_eps] 
      ON [if_submission].[submissionid] = [if_rti_eps].[submissionid] 
WHERE [if_submission].[taxyear] = 2016 
    AND (**IIF([if_submission].[submissiontypeid] = 8, 
     [payrollruns].[payemonth] = 5, 
       [if_submission].[periodnumber] = 5)**) 
    AND ([if_submission].[submissiontypeid] = 8 
      OR [if_submission].[submissiontypeid] = 10) 
    AND [if_submission].[testinlive] = 0 
ORDER BY submissiontypeid 

這是位我需要

IIF([if_submission].[submissiontypeid] = 8, 
     [payrollruns].[payemonth] = 5, 
       [if_submission].[periodnumber] = 5) 

任何人的幫助有任何想法掙扎？

感謝

Answer 1

試試這個

AND 5 = CASE WHEN [if_submission].[submissiontypeid] = 8 
      THEN [payrollruns].[payemonth] 
      ELSE [if_submission].[periodnumber] 
     END 

Answer 2

您可以使用CASE expression：

簡單的CASE表達式：

CASE input_expression 
    WHEN when_expression THEN result_expression [ ...n ] 
    [ ELSE else_result_expression ] 
END 

搜索CASE表達式：

CASE 
    WHEN Boolean_expression THEN result_expression [ ...n ] 
    [ ELSE else_result_expression ] 
END 

Answer 3

如果您正在使用SQL SERVER 2012+然後IIF支持，但語法必須是有點不同。

IIF([if_submission].[submissiontypeid] = 8,[payrollruns].[payemonth], 
              [if_submission].[periodnumber]) = 5 

否則我會做到這一點使用AND/OR邏輯

...... 
(
(
[if_submission].[submissiontypeid] = 8 and [payrollruns].[payemonth] = 5 
) 
or 
(
[if_submission].[periodnumber] = 5 and [if_submission].[submissiontypeid] <> 8 
) 
) 
.....