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我試圖做出各種按鈕,當它們被點擊時將改變音頻文件的位置(右/左)。第一個音頻「風」工作正常。它通過單擊播放並根據按下哪個按鈕來更改位置。然而,第二個音頻「教堂鈴聲」不改變位置。我真的不確定這是如何工作的,所以我嘗試改變每個事物的名稱以給它一個唯一的標識符,但它不起作用。如何使用Web Audio API更改點擊音頻位置?
<script>
let audioContext = new AudioContext();
// Create a (1st-order Ambisonic) Songbird scene.
let songbird = new Songbird(audioContext);
// Send songbird's binaural output to stereo out.
songbird.output.connect(audioContext.destination);
// Set room acoustics properties.
let dimensions = {
width : 4,
height : 2.5,
depth : 3
};
let materials = {
left : 'plaster-rough',
right : 'plaster-rough',
front : 'plaster-rough',
back : 'plaster-rough',
down : 'plywood-panel',
up : 'plaster-rough'
};
songbird.setRoomProperties(dimensions, materials);
// Create an audio element. Feed into audio graph.
let audioElement = document.createElement('audio');
audioElement.src = 'wind.ogg';
let audioElementSource =
audioContext.createMediaElementSource(audioElement);
// Create a Source, connect desired audio input to it.
let source = songbird.createSource();
audioElementSource.connect(source.input);
// The source position is relative to the origin
// (center of the room).
source.setPosition(0.0, 8.9, 0);
// Playback the audio.
function wind() {
audioElement.play();
audioElement.loop = true;
}
function right1() {
source.setPosition(-0.9, 8.9, 0);
}
function right2() {
source.setPosition(-2, 8.9, -1);
}
function right3() {
source.setPosition(-1, 8.9, -2);
}
function right4() {
source.setPosition(0, 8.9, -3);
}
function right5() {
source.setPosition(1, 8.9, -2);
}
function right6() {
source.setPosition(2, 8.9, -1);
}
function right7() {
source.setPosition(0.9, 8.9, 0);
}
function right8() {
source.setPosition(0, 8.9, 0);
}
</script>
<!-- Church Bell -->
<script>
let audioContext1 = new AudioContext();
// Create a (1st-order Ambisonic) Songbird scene.
let songbird1 = new Songbird(audioContext1);
// Send songbird's binaural output to stereo out.
songbird1.output.connect(audioContext1.destination);
// Set room acoustics properties.
let dimensions = {
width : 4,
height : 2.5,
depth : 3
};
let materials = {
left : 'plaster-rough',
right : 'plaster-rough',
front : 'plaster-rough',
back : 'plaster-rough',
down : 'plywood-panel',
up : 'plaster-rough'
};
songbird1.setRoomProperties(dimensions, materials);
// Create an audio element. Feed into audio graph.
let audioElement1 = document.createElement('audio');
audioElement1.src = 'churchbells.ogg';
let audioElementSource1 =
audioContext1.createMediaElementSource(audioElement1);
// Create a Source, connect desired audio input to it.
let source1 = songbird1.createSource();
audioElementSource1.connect(source1.input);
// The source position is relative to the origin
// (center of the room).
source1.setPosition(-99, 8.9, 0);
function churchbells() {
// Playback the audio.
audioElement1.play();
}
function churchbellsright1() {
source1.setPosition(99, 8.9, 0);
}
</script>
<script src="https://raw.githubusercontent.com/google/songbird/master/build/songbird.js"></script>
<button onclick="play();">play</button>
<button onclick="right1();">right 1</button>
<button onclick="right2();">right 2</button>
<button onclick="right3();">right 3</button>
<button onclick="right4();">right 4</button>
<button onclick="right5();">right 5</button>
<button onclick="right6();">right 6</button>
<button onclick="right7();">right 7</button>
<button onclick="right8();">right 8</button>
<button onclick="churchbellsright1();">right 8</button>
這確實使它的工作,謝謝。但是,我意識到我擁有的第二個音頻不能以相同的方式工作。我用代碼更新了我原來的問題。我對此很新,所以我不知道如何解決這個問題。我嘗試改變第二個音頻(教堂鈴聲)中的所有名稱,給它一個唯一的標識符(source1 vs source,audioelement1 vs audioelement等),但它不起作用。如果我把教堂鈴聲功能放在最上面,它會播放音頻,但不會改變位置。當它放置在代碼中時,音頻和位置都不起作用。任何想法如何做一個以上的工作? – user2454060
爲'source','play'和'right1'等創建另一個不同名稱的副本應該可以工作。下面是我提出的一個簡單示例,它每次播放兩個:https://gist.github.com/tfogo/b80a3e4ea184c0c653f0ee1b1349a4dc它從'play()'返回源,以便您可以用不同的音樂文件調用它,並且可以將其分配給不同的變量。這不是最乾淨的代碼,但它的工作原理。最好讓你的函數可以重用,而不是一遍又一遍地複製它們,但內容略有不同。 – tfogo
它看起來像工作。非常感謝,我很放心,我不知道我是如何克服這個問題的。 – user2454060