如何將此SQL語句轉換爲PostgreSQL？

Question

我有一個MySQL語句，它不會在PostgreSQL服務器上運行。

原來這裏是MySQL查詢：

SELECT count(*) AS howmany 
FROM members 
WHERE member_status =1 
AND member_sex = 'male' 
AND (YEAR('2015-12-31') - YEAR(member_birthdate)) - 
    (RIGHT('2015-12-31', 5) < RIGHT(member_birthdate, 5)) 
BETWEEN 27 AND 40; 

這是我的方法：

SELECT COUNT(*) AS howmany FROM members 
WHERE member_status =1 
AND member_sex ='male' 
AND (EXTRACT(YEAR FROM '2015-12-31'::date) - EXTRACT(YEAR FROM member_birthdate)) 
BETWEEN 27 AND 40; 

的目標是什麼，我想知道有多少成員年27至40歲之間的資格日期2015-12-31。 我不知道如何轉換查詢的右側部分。

Answer 1

可以使用AGE功能：

SELECT COUNT(*) AS howmany 
FROM members 
WHERE member_status =1 
    AND member_sex ='male' 
    AND extract(year from age(timestamp '2015-12-31', member_birthdate)) 
     BETWEEN 27 AND 40;