爲什麼cakephp引發數據庫錯誤？

Question

當我試圖向數據庫中插入一張新發票時，cakephp會拋出一個錯誤，說它無法在where子句中找到列relationship.partytwo。我試圖實現的是確保發送發票的用戶在發送發票之前在relationship_users數據庫中與收到發票的人之間存在活動關係，可悲的是我所得到的只是數據庫錯誤。

這裏是我的表結構

invoices - id, to, biller, subject, description, datecreated, duedate 
relationships_users - id, partyone, partytwo, expirydate,active 

這裏是關係模型

<?php 

class Relationship extends AppModel 
{ 

    var $name = 'Relationship'; 
    public $useTable = 'relationships_users'; 
    public $primaryKey = 'id'; 
    public $belongsTo = array(
     'Invoice' => 
      array(
       'className'    => 'Invoice', 
       'joinTable'    => 'invoice', 
       'foreignKey'    => 'invoice_id')); 
    public $belongsTo = array(
     'User' =>array(
      'className' => 'User', 
      'foreignKey' =>'partyone','partytwo', 
      'associationForeignKey' => 'username', 
      )); 

    var $validate = array(
     'date' => array(
      'rule' => array(
       'datevalidation', 
       'systemDate' 
      ), 
      'message' => 'Current Date and System Date is mismatched' 
     ), 
     'partytwo' => array(
      'userExists' => array(
       'rule' => array(
        'userExists', 
       ), 
       'message' => 'That username doesnt exist.' 
      ), 
     ), 
    ); 

    function datevalidation($field = array(), $compare_field = null) 
    { 
     if ($field['date'] > $compare_field) 
      return TRUE; 
     else 
      return FALSE; 
    } 

    function userExists($check) 
    { 
     $userExists = $this->User->find('count', array('conditions' => array('User.username'=>$check))); 
     if ($userExists == 1) { 
      return TRUE; 
     } 
     else 
      return FALSE; 
    } 

} 

這裏是我的發票模型

<?php 
App::uses('AuthComponent', 'Controller/Component'); 

class Invoice extends AppModel{ 
     var $name='Invoice'; 
     public $useTable = 'invoices'; 
     public $primaryKey = 'id'; 
     public $hasMany = array(
     'Relationship' =>array(
      'className' => 'Relationship', 
      'foreignKey' =>'relationship_id', 
     )); 
     var $validate = array(
      'to' => array(
       'relationshipExists' => array(
        'rule' => array(
         'relationshipExists', 
         ), 
        'message' => 'sorry you dont have a relationship with that user.' 
        ), 
       ), 
      ); 


     public function relationshipExists($check){ 
      if($this->hasAny(array('Relationship.partytwo'=>current($check)))) 
      { 
       return TRUE; 
      } 
      else 
      { 
       return FALSE; 
      } 
     } 

    } 

這裏是我的addinvoice功能

public function addinvoice(){ 
    $this->set('title_for_layout', 'Create Invoice'); 
    $this->set('stylesheet_used', 'homestyle'); 
    $this->set('image_used', 'eBOXLogoHome.jpg'); 
    $this->layout='home_layout'; 

    if($this->request->is('post')){ 
     pr($this->Invoice->set($this->request->data)); 
     if($this->Invoice->validates(array('fieldList'=>array('to','Invoice.relationshipExists')))){ 
     // $this->Relationship->create(); 
      $this->Invoice->save($this->request->data); 
      $this->Session->setFlash('The invoice has been saved'); 
     }}else { 
       $this->Session->setFlash('The invoice could not be saved. Please, try again.'); 
      } 
    } 

Answer 1

A hasMany外鍵應該是在的其他表中。如果RelationshiphasManyInvoices，Invoices必須有外鍵relationship_id。

似乎要建模什麼是belongsTo，其中Relationship屬於關聯的Invoice，這意味着外鍵是在Relationship模型/表。