結合兩個查詢

Question

我有以下2個查詢其預期工作：

declare @user varchar(3) 
declare @phrase varchar(255) 

set @user = 'xyz' 
set @phrase = '%nav%' 

select ug.*, wap.*, w.* 
from user_groups ug 
inner join widget_access_permissions wap on ug.id = wap.allowed 
inner join widgets w on wap.widget_id = w.widget_id 
where ug.employee_code = @user 
and w.widget_name like @phrase 

select w.widget_id, ug.*, wdp.*, w.* 
from user_groups ug 
inner join widget_deny_permissions wdp on ug.id = wdp.denied 
inner join widgets w on wdp.widget_id = w.widget_id 
where ug.employee_code = @user 
and w.widget_name like @phrase 

第一個查詢顯示的記錄進行@user訪問基於所提供的任何@phrase部件。第二個查詢顯示@user根據提供的@phrase無法訪問的任何小部件的記錄。

我如何結合這兩個查詢轉換爲1，所以如果有人基於一組接入，而是因爲他是這是在拒絕表拒絕另一組，他沒有能看到的結果嗎？

我不知道如果我的最後一句話是有道理的......

編輯：添加的表名，表列和一個小樣本數據：

user_groups 

table 
id 
display_value 
employee_code 
dept 
persnl_typ_code 

sample row 1 
1000 
group 1 
xyz 
i.t. 
gen 

sample row 2 
1008 
group 2 
xyz 
i.t. 
gen 

========== 

widget_access_permissions 

table 
id 
widget_id 
allowed 

sample row 
0 
0 
1000 

========== 

widget_deny_permissons 

table 
id 
widget_id 
denied 

sample row 
0 
0 
1008 

========== 

widgets 

table 
widget_id 
widget_name 
widget_description 
widget_header 
widget_sub_header 
widget_content 

sample row 
0 
widget name goes here 
widget description goes here 
widget header goes here 
widget sub header goes here 
widget content goes here 

Answer 1

既然你正在使用SQL Server 2005，您可以使用EXCEPT：

select w.* 
from user_groups ug 
inner join widget_access_permissions wap on ug.id = wap.allowed 
inner join widgets w on wap.widget_id = w.widget_id 
where ug.employee_code = @user 
and w.widget_name like @phrase 
EXCEPT 
select w.* 
from user_groups ug 
inner join widget_deny_permissions wdp on ug.id = wdp.denied 
inner join widgets w on wdp.widget_id = w.widget_id 
where ug.employee_code = @user 
and w.widget_name like @phrase 

Thi S可在​​第一（允許）查詢的結果，並減去的第二（拒絕）查詢的結果，讓你只用那些在允許用戶和沒有否認小部件。

注意我已經改變了原來的SELECT清單，EXCEPT需要兩個查詢有（有效）相同SELECT名單，並在我看來，你有興趣在什麼是小部件。

Answer 2

如果我理解正確的話，你想工會的權限（最嚴格的方法），由此如果用戶在一組被允許的，而在另一個否認，他應該得到的是小工具，如果是這樣的話，你可以這樣做，

declare @user varchar(3) 
declare @phrase varchar(255) 

set @user = 'xyz' 
set @phrase = '%nav%' 

select ug.*, wap.*, w.* 
from user_groups ug 
inner join widget_access_permissions wap on ug.id = wap.allowed 
inner join widgets w on wap.widget_id = w.widget_id 
where ug.employee_code = @user 
and w.widget_name like @phrase 
and w.widget_id NOT IN (
     select w.widget_id 
     from user_groups ug 
     inner join widget_deny_permissions wdp on ug.id = wdp.denied 
     inner join widgets w on wdp.widget_id = w.widget_id 
     where ug.employee_code = @user 
     and w.widget_name like @phrase 
     ) 

Answer 3

簡單的方法是使用子查詢：

declare @user varchar(3) 
declare @phrase varchar(255) 

set @user = 'xyz' 
set @phrase = '%nav%' 

select ug.*, wap.*, w.* 
from user_groups ug 
inner join widget_access_permissions wap on ug.id = wap.allowed 
inner join widgets w on wap.widget_id = w.widget_id 
where ug.employee_code = @user 
and w.widget_name like @phrase 
and w.WidgetId not in (

select w.widget_id 
from user_groups ug 
inner join widget_deny_permissions wdp on ug.id = wdp.denied 
inner join widgets w on wdp.widget_id = w.widget_id 
where ug.employee_code = @user 
and w.widget_name like @phrase 
) 

不知道該如何表現將是這個。

編輯：

我想你可能能夠通過刪除子查詢的需要：

declare @user varchar(3) 
declare @phrase varchar(255) 

set @user = 'xyz' 
set @phrase = '%nav%' 

select ug.*, wap.*, w.* 
from user_groups ug 
inner join widget_access_permissions wap on ug.id = wap.allowed 
inner join widgets w on wap.widget_id = w.widget_id 

Left Join widget_deny_permissions wdp on ug.id = wdp.denied 
         and w.widget_id = wdp.widget_id 
where ug.employee_code = @user 
and w.widget_name like @phrase 
and wdp.Id Is Null 

這將取決於你的架構和數據