在mysql查詢中按名稱，日期，日期排序？

Question

我有這個輸入。

October 21 , 2010 
October 14 , 2007 
October 08 , 2010 
March 19 , 2009 
June 25 , 2009 
June 21 , 2013 
June 21 , 2013 
June 19 , 2006 
June 01 , 2009 
July 26 , 2013 
July 25 , 2012 
July 23 , 2013 
July 19 , 2013 
July 01 , 2009 
January 31 , 2013 
January 23 , 2013 
January 23 , 2011 
January 19 , 2013 
January 01 , 2000 
February 17 , 2011 
February 16 , 1998 
December 25 , 2003 
August 31 , 2013 
August 04 , 2013 
August 03 , 2013 
August 03 , 2013 
August 03 , 2013 
April 26 , 2013 
April 26 , 2013 
April 19 , 2005 

我想訂購，使最新的日期是在頂部..但我似乎無法做到這一點，有人可以提供一個解決方案？

這是我的SQL：

$sql = "SELECT * FROM $tbl_name WHERE Length(Year) > 7 AND `Title` 
LIKE '%" . $q . "%' AND `Genres` LIKE '%" . $genre . "%' AND `Actors` 
LIKE '%" . $actor . "%' AND `Year` <> 'Unknown' 
ORDER BY `Year` DESC LIMIT $start, $limit"; 

Answer 1

所以，這是2列，對不對？

然後像這樣做：

SELECT 
STR_TO_DATE(CONCAT(month_day_column, ', ', year_column), '%M %d, %Y') AS your_ISO_conform_date 
FROM yourTable 
ORDER BY your_ISO_conform_date DESC 

• 閱讀更多關於str_to_date()here。

• 和here是關於格式的一些信息，你必須爲參數提供給str_to_date()

Answer 2

我不使用MySQL的工作，主要是SQL Server中，我發現在一秒鐘內這個鏈接：https://dev.mysql.com/doc/refman/5.6/en/date-and-time-functions.html#function_str-to-date

select str_to_date('October 21 , 2010', '%M %d,%Y')