按加入日期排序查詢

Question

請有人可以幫我。我需要加入這兩個查詢和小時分組。查詢結果可能會有很多天。

結果：Query1

SELECT DATE_FORMAT(Venta.fechaImpresion, "%h") AS fechaImpresion2, COUNT(*) AS total 
FROM `Venta` 
WHERE Venta.fechaImpresion LIKE "2016-05-02 %" 
GROUP BY HOUR(Venta.fechaImpresion) , DAY(Venta.fechaImpresion) 
LIMIT 0 , 30 

結果：Query2

SELECT DATE_FORMAT(Venta.fechaImpresion,"%h") as fechaImpresion FROM `Venta` 
where Venta.fechaImpresion >= "2016-05-02" and Venta.fechaImpresion <= "2016-05-09" 
GROUP BY hour(Venta.fechaImpresion) 

，如果我嘗試在一個查詢中加入的結果是零。

SELECT DATE_FORMAT(Venta.fechaImpresion, "%h") AS fecha, dia1.total AS total1 
FROM `Venta` 
LEFT JOIN (

SELECT DATE_FORMAT(Venta.fechaImpresion, "%h") AS fechaImpresion 
FROM `Venta` 
WHERE Venta.fechaImpresion >= "2016-05-02" 
AND Venta.fechaImpresion <= "2016-05-09" 
GROUP BY HOUR(Venta.fechaImpresion) 
)fecha ON fecha.fechaImpresion = Venta.fechaImpresion 
LEFT JOIN (

SELECT DATE_FORMAT(Venta.fechaImpresion, "%h") AS fechaImpresion2, COUNT(*) AS total 
FROM `Venta` 
WHERE Venta.fechaImpresion LIKE "2016-05-02 %" 
GROUP BY HOUR(Venta.fechaImpresion) , DAY(Venta.fechaImpresion) 
)dia1 ON (dia1.fechaImpresion2 = fecha.fechaImpresion) 
WHERE Venta.fechaImpresion >= "2016-05-02" 
AND Venta.fechaImpresion <= "2016-05-09" 
GROUP BY HOUR(Venta.fechaImpresion) 

Answer 1

你可以嘗試這樣的

選擇b.second表列中，*。從第一臺，B秒錶，其中a.date列= b.date列

Answer 2

我會建議爲表格使用兩個單獨的句柄。類似這樣的：

SELECT DATE_FORMAT(v1.fechaImpresion, "%h") AS fechaImpresion2, COUNT(v1.*) AS total, DATE_FORMAT(v2.fechaImpresion,"%h") as fechaImpresion 
FROM `Venta` v1, 'Venta' v2 where v1.fechaImpresion = v2.fechaImpresion 

然後，您可以根據需要應用各種日期標準。