通過計數子查詢內的匹配數量來訂購查詢

Question

我正在計算子查詢內匹配的數量以排序結果。

查詢我想：

SELECT recipes.*, (SELECT COUNT(ingredient_id) FROM recipes WHERE ingredient_id IN(1,3))   AS ingredient_matches 
FROM recipes 
INNER JOIN ingredients 
ON recipes.id = ingredients.recipe_id 
INNER JOIN ingredients_available 
ON ingredients.ingredient_id = ingredients_available.id 
GROUP BY recipes.id 
ORDER BY ingredient_matches DESC; 

數據庫結構：

recipes: 
id, name 
ingredients: 
id, recipe_id, ingredient_id 
ingredients_available: 
id, name 
tags: 
id, recipe_id, tag_id 
tags_available: 
id, name 

以下作品中的查詢，但我希望能有不匹配的訪問成份，所以我可以說，他們需要他們如果這是有道理的？

SELECT recipes.*, COUNT(ingredients.id) AS ingredient_matches 
FROM recipes 
INNER JOIN ingredients 
ON recipes.id = ingredients.recipe_id 
INNER JOIN ingredients_available 
ON ingredients.ingredient_id = ingredients_available.id 
WHERE ingredient_id IN (1, 5) 
GROUP BY recipes.id 
ORDER BY ingredient_matches DESC; 

Answer 1

http://sqlfiddle.com/#!2/3f9ef/15

當時所期望的結果。這是因爲我沒有確定子查詢中的recipes_id = ingredients.recipe_id。

Answer 2

是否低於工作？：

SELECT recipes.*, COUNT(ingredients.id) AS ingredient_matches 
FROM recipes 
INNER JOIN ingredients 
ON recipes.id = ingredients.recipe_id 
LEFT JOIN ingredients_available 
ON ingredients.ingredient_id = ingredients_available.id 
WHERE ingredient_id IN (1, 5) 
GROUP BY recipes.id 
ORDER BY ingredient_matches DESC;