的Python：用引號括起來

Question

我有一個字符串如空格分隔字符串中的每個單詞：

line="a sentence with a few words" 

我想上述轉換的一個字符串中的每一個在雙引號的話，如：

"a" "sentence" "with" "a" "few" "words" 

有什麼建議嗎？

Answer 1

拆分行成的話，用引號括每個字，然後重新加入：

' '.join('"{}"'.format(word) for word in line.split(' ')) 

Answer 2

既然你說 -

我想上述轉換的字符串與每個在雙引號

的話

您可以使用下面的正則表達式 -

>>> line="a sentence with a few words" 
>>> import re 
>>> re.sub(r'(\w+)',r'"\1"',line) 
'"a" "sentence" "with" "a" "few" "words"' 

這將考慮到標點​​符號等，以及（如果這真的是你想要的東西） -

>>> line="a sentence with a few words. And, lots of punctuations!" 
>>> re.sub(r'(\w+)',r'"\1"',line) 
'"a" "sentence" "with" "a" "few" "words". "And", "lots" "of" "punctuations"!' 

Answer 3

或者你可以簡單的東西（更實現，但對於初學者更容易）通過搜索每個空間引用然後切割空間之間的任何東西，添加「之前和之後，然後打印它。

quote = "they stumble who run fast" 
first_space = 0 
last_space = quote.find(" ") 
while last_space != -1: 
    print("\"" + quote[first_space:last_space] + "\"") 
    first_space = last_space + 1 
    last_space = quote.find(" ",last_space + 1) 

上面的代碼會爲你輸出如下：

"they" 
"stumble" 
"who" 
"run" 

Answer 4

第一個答案錯過了原帖的一個實例。最後一個字符串/單詞「fast」未打印。 該解決方案將打印最後一個字符串：

quote = "they stumble who run fast" 

start = 0 
location = quote.find(" ") 

while location >=0: 
    index_word = quote[start:location] 
    print(index_word) 

    start = location + 1 
    location = quote.find(" ", location + 1) 

#this runs outside the While Loop, will print the final word 
index_word = quote[start:] 
print(index_word) 

這是結果：

they 
stumble 
who 
run 
fast