加入兩列兩列SQL Server 2008 R2

Question

我有兩個表，我想加入到一起。一個是具有各種信息位的表格，另一個是維度視圖，各種定義表。與所需信息的表看起來像這樣

VISIT ID | ATN_DR_NO | ADM_DR_NO |... 
12345678 | 987654 | 123456 |... 

凡ATN_DR_NO是主治醫師ID號和ADM_DR_NO是承認醫生ID。我有一個具有醫生ID號及其對應名稱的第二個表像這樣

src_prct_no | pract_rpt_name | ... 
987654  | Dr. A   | ... 
123456  | Dr. B   | ... 
... 

我試圖做到的是在一個表，我有以下

VISIT ID | ATN_DR_NO | ATN DR NAME | ADM_DR_NO | ADM DR NAME 
12345678 | 987654 | DR. A  | 123456 | DR. B 

取得成果我不知道如何加入多欄。

這裏是我在整個工作查詢：

SET ANSI_NULLS OFF 
GO 
-- VARIABLE DECLARATION AND INITIALIZATION 
DECLARE @SD DATETIME; 
DECLARE @ED DATETIME; 
SET @SD = '2014-01-01'; 
SET @ED = '2014-02-01'; 

/* 
----------------------------------------------------------------------- 
THIS QUERY WILL GET ALL THE FRONT END INFORMATION REQUIRED FOR HOSIM 
AND INSERT IT INTO A TABLE THAT WILL GET MATCHED UP WITH THE DISCHARGE 
ORDERS TABLE 
----------------------------------------------------------------------- 
START OF QUERY 1 
----------------------------------------------------------------------- 
*/ 
-- TABLE DECLARATION 
DECLARE @T1 TABLE (
    [ENCOUNTER ID]    VARCHAR(200) 
    , /*NEW*/MRN     VARCHAR(20)  
    , /*NEW*/DOB     DATETIME 
    , /*NEW*/GENDER    VARCHAR(10) 
    , FINANCIALCLASSORIG   VARCHAR(200) 
    , [ADMIT DATE]    DATE 
    , [ADMIT TIME]    TIME 
    , [ADMIT FROM]    VARCHAR(200) 
    , [DISCHARGE DATE]   DATE 
    , [DISCHARGE TIME]   TIME 
    , /*TEST*/[ADMITTING MD NO] VARCHAR(200) 
    , /*TEST*/[ADMITTING MD]  VARCHAR(200) 
    , /*TEST*/[ATTENDING MD NO] VARCHAR(200) 
    , /*TEST*/[ADTTENDING MD] VARCHAR(200) 
    , [MS DRG]     VARCHAR(200) 
    , LOS      VARCHAR(20) 
    , [ADMIT PATIENT STATUS]  VARCHAR (10) 
    , [DISCHARGE PATIENT STATUS] VARCHAR(10) 
    , [DISCHARGE DISPOSITION] VARCHAR (200) 
    , [DISCHARGE UNIT]   VARCHAR (200) 
) 
-- WHAT GETS INSERTED INTO @T1 
INSERT INTO @T1 
SELECT 
A.[VISIT ID] 
, A.MRN 
, A.DOB 
, A.GENDER 
, A.FINANCIALCLASSORIG 
, A.[ADMIT DATE] 
, A.[ADMIT TIME] 
, A.[ADMIT FROM] 
, A.[DISCHARGE DATE] 
, A.[DISCHARGE TIME] 
, A.[ADMITTING DR NO] 
, A.[ADMITTING DR] 
, A.[ATTENDING DR NO] 
, A.[ATTENDING DR] 
, A.[MS DRG] 
, A.LOS 
, A.[ADMIT PATIENT STATUS] 
, A.[DISCHARGE PATIENT STATUS] 
, A.[DISCHARGE DISPOSITION] 
, A.[DISCHARGE UNIT] 
-- END @T1 INSERT SELECTION 

-- WHERE IT ALL COMES FROM 
-- COLUMN SELECTION 
FROM (
    SELECT DISTINCT PAV.PtNo_Num  AS [VISIT ID] 
    , /*NEW*/PAV.Med_Rec_No    AS MRN 
    , /*NEW*/PAV.Pt_Birthdate   AS DOB 
    , /*NEW*/PAV.Pt_Sex     AS GENDER 
    , PD.pyr_name      AS [FinancialClassOrig] 
    , CAST(PAV.Adm_Date AS DATE)  AS [ADMIT DATE] 
    , CAST(PAV.vst_start_dtime AS TIME) AS [ADMIT TIME] 
    , PAV.Adm_Source     AS [ADMIT FROM] 
    , CAST(PAV.Dsch_Date AS DATE)  AS [DISCHARGE DATE] 
    , CAST(PAV.Dsch_DTime AS TIME)  AS [DISCHARGE TIME] 
    , /*TEST*/PAV.Adm_Dr_No    AS [ADMITTING DR NO] 
    , /*TEST*/PDV.pract_rpt_name  AS [ADMITTING DR] 
    , /*TEST*/PAV.Atn_Dr_No    AS [ATTENDING DR NO] 
    , /*TEST*/PDV.pract_rpt_name  AS [ATTENDING DR] 
    , PAV.drg_no      AS [MS DRG] 
    , PAV.Days_Stay      AS [LOS] 
    , 'I'        AS [ADMIT PATIENT STATUS] 
    , 'I'        AS [DISCHARGE PATIENT STATUS] 
    , DDM.dsch_disp_desc    AS [DISCHARGE DISPOSITION] 
    , VR.ward_cd      AS [DISCHARGE UNIT] 

    -- FROM DB(S) 
    FROM smsdss.BMH_PLM_PtAcct_V PAV 
     JOIN smsdss.pract_dim_v PDV 
     ON PAV.Adm_Dr_No = PDV.src_pract_no 
     /*TEST*/AND PAV.Atn_Dr_No = PDV.src_pract_no 
     JOIN smsdss.pyr_dim PD 
     ON PAV.Pyr1_Co_Plan_Cd = PD.pyr_cd 
     JOIN smsmir.vst_rpt VR 
     ON PAV.PtNo_Num = VR.acct_no 
     JOIN smsdss.dsch_disp_mstr DDM 
     ON VR.dsch_disp = DDM.dsch_disp 

    -- FILTER(S) 
    WHERE PAV.Dsch_Date >= @SD 
    AND PAV.Dsch_Date < @ED 
    AND PAV.Plm_Pt_Acct_Type = 'I' 
    AND PAV.PtNo_Num < '20000000' 
    AND PDV.src_spclty_cd = 'HOSIM' 
    AND PD.orgz_cd = 'S0X0' 
    AND PD.pyr_name != '?' 
) A 

SELECT * FROM @T1 

你覺得我應該創建像@ADM_DR和@ATN_DR和WHERE子句中的變量設置它們等於select語句，將讓他們？ 謝謝，

Answer 1

您再次回到表格中，所以看起來好像您是從同一張桌子兩次（主診醫生查找，一個用於接受醫生查找）。

SELECT a.doc_name as attending_name, 
     b.somefield, 
     a2.doc_name as admitting_name 

FROM doctors a, 
    someothertable b, 
    doctors a2 

WHERE a.doc_id = b.attending_doc_id 
    AND a2.doc_id = b.admitting_doc_id 
    AND b.record_id = <whatever> 

和你內心的加盟，目標的第一個醫生，在加入了A2目標的第二個醫生。

赦免僞代碼，但我認爲你明白了。您會注意到a和a2都從doctors表中獲取doc_name字段，但它們已加入b表中的不同ID。