迭代XPath以獲取表名

Question

我想迭代XPath以獲取表名。這是我的Xpath值。

PromoteData/Table[@Id='auditSet']/Table[@Id='auditSetMapping']/Table[@Id='appExpr'] 

請指導我如何迭代此XPath的每個值。預期結果會像 'auditSet'， 'auditSetMapping'， 'appExpr'

Answer 1

import java.io.IOException; 
import java.io.StringReader; 

import javax.xml.parsers.DocumentBuilderFactory; 
import javax.xml.parsers.ParserConfigurationException; 
import javax.xml.xpath.XPath; 
import javax.xml.xpath.XPathConstants; 
import javax.xml.xpath.XPathExpressionException; 
import javax.xml.xpath.XPathFactory; 

import org.w3c.dom.Document; 
import org.w3c.dom.Element; 
import org.w3c.dom.NodeList; 
import org.xml.sax.InputSource; 
import org.xml.sax.SAXException; 


public class XPathExtract { 

    public static void main(String[] args) throws SAXException, IOException, 
     ParserConfigurationException, XPathExpressionException { 
    String xml = "..."; 

    // Parse the XML as DOM 
    Document doc = DocumentBuilderFactory.newInstance().newDocumentBuilder() 
     .parse(new InputSource(new StringReader(xml))); 

    // Create a XPath instance 
    XPath xpath = XPathFactory.newInstance().newXPath(); 

    // Evaluate the XPath. The result is a NodeList 
    NodeList nodes = (NodeList) xpath.evaluate(
     "PromoteData/Table[@Id='auditSet']/Table[@Id='auditSetMapping']/Table[@Id='appExpr']", 
     doc, XPathConstants.NODESET); 

    // Iterate over the nodes 
    for (int i = 0; i < nodes.getLength(); i++) { 
     // node.item(i) is a Node. If you are sure, it is always an Element you can do a cast 
     Element el = (Element) nodes.item(i); 
     // Process the element 
     System.out.println(el.getAttribute("Id")); 
    } 
    } 
}