要建立在stewe的答案,關閉編譯器高級開啓爲您提供了與一堆污染了全局命名空間的腳本一個字母變量。所以,我只是把它包裝在一個匿名函數調用就像這樣:
(function() { function g(a){var b=typeof a;if("object"==b)if(a){if(a instanceof Array)return"array";if(a instanceof Object)return b;var c=Object.prototype.toString.call(a);if("[object Window]"==c)return"object";if("[object Array]"==c||"number"==typeof a.length&&"undefined"!=typeof a.splice&&"undefined"!=typeof a.propertyIsEnumerable&&!a.propertyIsEnumerable("splice"))return"array";if("[object Function]"==c||"undefined"!=typeof a.call&&"undefined"!=typeof a.propertyIsEnumerable&&!a.propertyIsEnumerable("call"))return"function"}else return"null"; else if("function"==b&&"undefined"==typeof a.call)return"object";return b};function h(a){a=""+a;if(/^\s*$/.test(a)?0:/^[\],:{}\s\u2028\u2029]*$/.test(a.replace(/\\["\\\/bfnrtu]/g,"@").replace(/"[^"\\\n\r\u2028\u2029\x00-\x08\x10-\x1f\x80-\x9f]*"|true|false|null|-?\d+(?:\.\d*)?(?:[eE][+\-]?\d+)?/g,"]").replace(/(?:^|:|,)(?:[\s\u2028\u2029]*\[)+/g,"")))try{return eval("("+a+")")}catch(b){}throw Error("Invalid JSON string: "+a);}function i(a,b){var c=[];j(new k(b),a,c);return c.join("")}function k(a){this.a=a} function j(a,b,c){switch(typeof b){case "string":l(b,c);break;case "number":c.push(isFinite(b)&&!isNaN(b)?b:"null");break;case "boolean":c.push(b);break;case "undefined":c.push("null");break;case "object":if(null==b){c.push("null");break}if("array"==g(b)){var f=b.length;c.push("[");for(var d="",e=0;e<f;e++)c.push(d),d=b[e],j(a,a.a?a.a.call(b,""+e,d):d,c),d=",";c.push("]");break}c.push("{");f="";for(e in b)Object.prototype.hasOwnProperty.call(b,e)&&(d=b[e],"function"!=typeof d&&(c.push(f),l(e,c),c.push(":"), j(a,a.a?a.a.call(b,e,d):d,c),f=","));c.push("}");break;case "function":break;default:throw Error("Unknown type: "+typeof b);}}var m={'"':'\\"',"\\":"\\\\","/":"\\/","\u0008":"\\b","\u000c":"\\f","\n":"\\n","\r":"\\r","\t":"\\t","\x0B":"\\u000b"},n=/\uffff/.test("\uffff")?/[\\\"\x00-\x1f\x7f-\uffff]/g:/[\\\"\x00-\x1f\x7f-\xff]/g; function l(a,b){b.push('"',a.replace(n,function(a){if(a in m)return m[a];var b=a.charCodeAt(0),d="\\u";16>b?d+="000":256>b?d+="00":4096>b&&(d+="0");return m[a]=d+b.toString(16)}),'"')};window.JSON||(window.JSON={});"function"!==typeof window.JSON.stringify&&(window.JSON.stringify=i);"function"!==typeof window.JSON.parse&&(window.JSON.parse=h); })();
現在,您可以撥打:
var JSONString = JSON.stringify({name: 'value'});
類似的帖子:HTTP://計算器。com/questions/191881/serializing-to-json-in-jquery – sberry
也許我真的很笨,但這對我來說也是一個完全的驚喜。看起來像JSON.org的腳本是要走的路。 – KevinM