SQL查詢錯誤，需要一些幫助

Question

我有了這個查詢應該退還一半的人，他們在過去一週買東西：

UPDATE main_data SET md.amount_current = md.amount_current + (bought.total/2) 
FROM main_data AS md 
INNER JOIN (
    SELECT DISTINCT sb.user_id, SUM(sb.spend) AS total 
    FROM shopitems_bought AS sb 
    LEFT JOIN shopitems AS si 
    ON sb.shopitem_id = si.id 
    WHERE sb.date_bought <= '2012-03-09' 
    AND sb.date_bought > DATE_ADD('2012-03-09', INTERVAL -7 DAY) 
    AND si.valid = 1 
    GROUP BY sb.user_id 
) AS bought ON bought.user_id = md.user_id 
WHERE md.valid = 1 

SELECT部分​​執行它自己就好了，並返回正確的數據（應該退還的ID和他們在那周花費的金額）。然而，作爲一個整體的查詢拋出一個錯誤，說我的SQL語法附近第2行有一個錯誤（我引用：'FROM main_data AS md INNER JOIN（SELECT DISTINCT sb.forum_id，SUM（sb.s'）。

我看不到我在做什麼錯

Answer 1

MySql uses a different syntax for join with update statements比你上面使用的是什麼試着改變你的查詢：。

UPDATE main_data md 
INNER JOIN (
    SELECT DISTINCT sb.user_id, SUM(sb.spend) AS total 
    FROM shopitems_bought AS sb 
    LEFT JOIN shopitems AS si 
    ON sb.shopitem_id = si.id 
    WHERE sb.date_bought <= '2012-03-09' 
    AND sb.date_bought > DATE_ADD('2012-03-09', INTERVAL -7 DAY) 
    AND si.valid = 1 
    GROUP BY sb.user_id 
) bought ON bought.user_id = md.user_id 
SET amount_current = md.amount_current - (bought.total/2) 
WHERE md.valid = 1 

注意，我改變

SET amount_current = md.amount_current + (bought.total/2) 

Ť Ø減去添加而不是：

SET amount_current = md.amount_current - (bought.total/2) 

Answer 2

沒有user_Id內內JOIN

UPDATE main_data SET md.amount_current = md.amount_current + (bought.total/2) 
FROM main_data AS md 
INNER JOIN (
    SELECT sb.user_id, DISTINCT sb.forum_id, SUM(sb.spend) AS total 
    FROM shopitems_bought AS sb 
    LEFT JOIN shopitems AS si 
    ON sb.shopitem_id = si.id 
    WHERE sb.date_bought <= '2012-03-09' 
    AND sb.date_bought > DATE_ADD('2012-03-09', INTERVAL -7 DAY) 
    AND si.valid = 1 
    GROUP BY sb.user_id 
) AS bought ON bought.user_id = md.user_id 
WHERE md.valid = 1