（PHP）這裏我的錯誤是什麼？

Question

表單上的數據未能保存在數據庫中。我找不到這裏有什麼問題。我已經檢查過輸入表單的名稱，這是完全正確的。我使用的PDO

if ($_POST) { 
$accountuname = ($_POST['accountuname']); 
$accountpassword = ($_POST['accountpassword']); 
$accounttype = ($_POST['accounttype']); 
$companyname = ($_POST['companyname']); 
$companyproduct = ($_POST['companyproduct']); 
$companyaddress = ($_POST['companyaddress']); 
$companycontactnum = ($_POST['companycontactnum']); 

$query = "INSERT INTO user_accounts SET USER_NAME=?, USER_PASS=?, USER_ACC_TYPE=?, COMPANY_NAME=?, COMPANY_PRODUCT=?, COMPANY_ADDRESS=?, COMPANY_CONTACTNUM=?"; 
$stmt = $conn->prepare($query); 
$stmt -> bindParam(1,$accountuname); 
$stmt -> bindParam(2,$accountpassword); 
$stmt -> bindParam(3,$accounttype); 
$stmt -> bindParam(4,$companyname); 
$stmt -> bindParam(5,$companyproduct); 
$stmt -> bindParam(6,$companyaddress); 
$stmt -> bindParam(7,$companycontactnum); 
$stmt -> execute(); 
}else{ 
header("location:index.php"); 
} 

Answer 1

更改SQL查詢來自：

INSERT INTO user_accounts SET USER_NAME=?, USER_PASS=?, USER_ACC_TYPE=?, COMPANY_NAME=?, COMPANY_PRODUCT=?, COMPANY_ADDRESS=?, COMPANY_CONTACTNUM=? 

要：

INSERT INTO user_accounts (USER_NAME, USER_PASS, USER_ACC_TYPE, COMPANY_NAME, COMPANY_PRODUCT, COMPANY_ADDRESS, COMPANY_CONTACTNUM) VALUES (?, ?, ?, ?, ?, ?, ?) 

INSERT INTO syntax.

Answer 2

如果您使用的mysqli，acording到documentation， bind_param（而不是bindParam ...也許你？使用的框架）函數期望的第一個參數是字符串，而不是一個int：

bind_param (string $types , mixed &$var1 [, mixed &$... ]) 

類型

A string that contains one or more characters which specify the types 

用於相應綁定變量：

i。相應變量具有類型整數

d對應變量具有類型雙重

及其對應變量的類型爲字符串

B中的對應變量是一個blob，將在數據包被髮送

，則應該更換1,2,3,4 ......爲「d，S ，b'（變量類型），它應該工作。

希望它有幫助！

Answer 3

您必須指定綁定的參數類型，並且您的查詢也不正確。

這裏是庫MySQLi正確的版本：

$query = "INSERT INTO user_accounts (USER_NAME, USER_PASS, USER_ACC_TYPE, COMPANY_NAME, COMPANY_PRODUCT, COMPANY_ADDRESS, COMPANY_CONTACTNUM) VALUES (?, ?, ?, ?, ?, ?, ?)"; 
$stmt = $conn->prepare($query); 

$stmt->bindParam("sssssss", $accountuname, $accountpassword, $accounttype, $companyname, $companyproduct, $companyaddress, $companycontactnum); 

// Set parameters and execute 
$accountuname = $_POST['accountuname']; 
$accountpassword = $_POST['accountpassword']; 
$accounttype = $_POST['accounttype']; 
$companyname = $_POST['companyname']; 
$companyproduct = $_POST['companyproduct']; 
$companyaddress = $_POST['companyaddress']; 
$companycontactnum = $_POST['companycontactnum']; 
$stmt->execute(); 

這裏是PDO正確的版本：

$query = "INSERT INTO user_accounts (USER_NAME, USER_PASS, USER_ACC_TYPE, COMPANY_NAME, COMPANY_PRODUCT, COMPANY_ADDRESS, COMPANY_CONTACTNUM) VALUES (:uname, :upass, :utype, :cname, :cproduct, :caddress, :ccontactnum)"; 
$stmt = $conn->prepare($query); 

$stmt->bindParam(':uname', $accountuname); 
$stmt->bindParam(':upass', $accountpassword); 
$stmt->bindParam(':utype', $accounttype); 
$stmt->bindParam(':cname', $companyname); 
$stmt->bindParam(':cproduct', $companyproduct); 
$stmt->bindParam(':caddress', $companyaddress); 
$stmt->bindParam(':ccontactnum', $companycontactnum); 

// Set parameters and execute 
$accountuname = $_POST['accountuname']; 
$accountpassword = $_POST['accountpassword']; 
$accounttype = $_POST['accounttype']; 
$companyname = $_POST['companyname']; 
$companyproduct = $_POST['companyproduct']; 
$companyaddress = $_POST['companyaddress']; 
$companycontactnum = $_POST['companycontactnum']; 
$stmt->execute(); 

對於mysqli的：在這個例子中，我假定所有發佈的數據是串，否則你將不得不改變bindParam函數中的'sssssss'。

瞭解更多關於準備好的發言here
瞭解更多關於MySQLi的INSERT語法here