如何使用戶自動跟蹤管理用戶註冊

Question

目前，我允許用戶在我的導軌應用程序（類似於推特）上跟隨另一個。

如果註冊到網站的新用戶自動關注管理員用戶，我很樂意。

Similar to how MySpace use to automatically make Tom your first friend 

下面是我用它來創建新用戶，並允許用戶彼此相隨。代碼（我知道這是一個非常廣泛的問題，但.....）

（可有人請指出我正確的方向，我怎麼能得到這個開始。我需要創建一個方法....在我的模型或添加代碼到控制器？）

新來的Rails請幫忙）.. 。:)

個USER控制器

class UsersController < ApplicationController 
    before_filter :admin_user,  only: [:destroy] 

    respond_to :html, :js 

    def new 
    @user = RegularUser.new 
    end 

    def index 
    @users = User.paginate(page: params[:page], :per_page => 100).search(params[:search]) 
    end 

    def destroy 
    User.find_by_username(params[:id]).destroy 
    flash[:success] = "User destroyed." 
    redirect_to users_url 
    end 

    def create 
    @user = RegularUser.new(params[:regular_user]) 
    if @user.save 
     UserMailer.registration_confirmation(@user).deliver 
     UserMailer.welcome_user(@user).deliver 
     sign_in @user 
     flash[:success] = "Welcome to the ClickOnComics!" 
     redirect_to (publishers_path) 
    else 
     render 'new' 
    end 
    end 

    private 

    def admin_user 
     redirect_to(root_path) unless current_user.admin? 
    end 

    def follow_admins 
     admins = User.find_by_admin(true) 
     admins.each do |admin| 
     self.follow!(admin) 
    end 
end 

class RelationshipsController < ApplicationController 
    before_filter :current_user 

    respond_to :html, :js 

def create 
    @user = User.find(params[:relationship][:followed_id]) 
    current_user.follow!(@user) 
    respond_with @user 
end 

    def destroy 
    @user = Relationship.find(params[:id]).followed 
    current_user.unfollow!(@user) 
    respond_with @user 
    end 

end 

模型

class Relationship < ActiveRecord::Base 

    attr_accessible :followed_id 

    belongs_to :follower, class_name: "User" 
    belongs_to :followed, class_name: "User" 

    validates :follower_id, presence: true 
    validates :followed_id, presence: true 
end 

class User < ActiveRecord::Base 
    attr_accessible :name, :email, :password, :password_confirmation 

    has_many :relationships, foreign_key: "follower_id", dependent: :destroy 
    has_many :followed_users, through: :relationships, source: :followed 

    has_many :reverse_relationships, foreign_key: "followed_id", 
           class_name: "Relationship", 
           dependent: :destroy 
    has_many :followers, through: :reverse_relationships, source: :follower 

    after_create :follow_admins 

    def follow_admins 
    admins = User.find_all_by_admin(true) 
     admins.each do |admin| 
     self.follow!(admin) 
    end 
    end 

    def following?(other_user) 
    relationships.find_by_followed_id(other_user.id) 
    end 

    def follow!(other_user) 
    relationships.create!(followed_id: other_user.id) 
    end 

    def unfollow!(other_user) 
    relationships.find_by_followed_id(other_user.id).destroy 
    end 

end 

我用這個教程，以幫助我建立特權管理用戶與用戶模式

http://ruby.railstutorial.org/chapters/updating-showing-and-deleting-users#sec-administrative_users

一個布爾管理屬性

SCHEMA

create_table "users", :force => true do |t| 
    t.string "name" 
    t.string "email" 
    t.string "role" 
    t.string "username" 
    t.timestamp "created_at",        :null => false 
    t.timestamp "updated_at",        :null => false 
    t.boolean "admin",     :default => false 
    t.string "password_reset_token" 
    t.timestamp "password_reset_sent_at" 
    end 

我需要創建一個定義user_admin方法？

Answer 1

在user.rb添加after_create過濾

after_create :follow_admin! 

def follow_admin! 
    relationships.create!(followed_id: admin_user.id) 
end 

Answer 2

在create行動sign_in前加

@user.follow! admin_user 

您需要首先獲取某種方式管理用戶。 好主意是使follow!，following?和unfollow!方法，以接受ID或對象作爲

def follow!(user_or_id) 
    id = (user_or_id.is_a?(User) ? user_or_id.id : user_or_id) 
    relationships.create!(followed_id: id) 
end