我有這樣的字符串：選擇分隔的字符串作爲Oracle SQL表
「寬度：10 | 7 | 20 | 45，身高：25 | 5 | 6 | 45，長度：35 | 6 | 3 | 4"
我期待寫一個選擇查詢，選擇這像一個表：
Width | Height | Length
-----------------------
10 | 25 | 35
7 | 5 | 6
20 | 6 | 3
45 | 45 | 4
請評論，如果您需要任何更多的信息。
你是指這個？在您的oracle中運行它：
WITH TEST_DATA AS (
SELECT
SUBSTR('Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4',
INSTR('Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4', 'Width:') + LENGTH('Width:'),
INSTR('Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4', ',', 1) - LENGTH('Width:') - 1) AS WIDTH,
SUBSTR('Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4',
INSTR('Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4', 'Height:') + LENGTH('Height:'),
INSTR('Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4', ',', INSTR('Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4', 'Height:'))
- INSTR('Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4', 'Height:') - LENGTH('Height:')) AS HEIGHT,
SUBSTR('Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4',
INSTR('Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4', 'Length:') + LENGTH('Length:')) AS LENGTH
FROM DUAL
)
SELECT
REGEXP_SUBSTR(WIDTH, '[^|]+', 1, ROWNUM) AS WIDTH,
REGEXP_SUBSTR(HEIGHT, '[^|]+', 1, ROWNUM) AS HEIGHT,
REGEXP_SUBSTR(LENGTH, '[^|]+', 1, ROWNUM) AS LENGTH
FROM TEST_DATA
CONNECT BY ROWNUM <= LENGTH(WIDTH)-LENGTH(REPLACE(WIDTH,'|'))+1
此解決方案可以使用任意數量的列（寬度，高度...）和值。
-- your test data
with data(val) as
(select 'Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4' from dual),
-- split by ,
cols as
(select regexp_substr(str, '[^,]+', 1, level) val
from (select val as str from data)
connect by regexp_substr((select val as str from data),
'[^,]+',
1,
level) is not null),
-- split by :
hdr_and_cols as
(select substr(val, 1, instr(val, ':') - 1) as hdr,
substr(val, instr(val, ':') + 1) as val
from cols),
-- split by |
hdr_lvl_vals as
(select distinct x.hdr,
level as entry,
regexp_substr(x.val, '[^|]+', 1, level) as val
from hdr_and_cols x
connect by regexp_substr(x.val, '[^|]+', 1, level) is not null)
select * from hdr_lvl_vals;
結果：
hdr entry value
---------------------
Height 1 25
Height 2 5
Height 3 6
Height 4 45
Length 1 35
Length 2 6
Length 3 3
Length 4 4
Width 1 10
Width 2 7
Width 3 20
Width 4 45
您可以格式化結果在你喜歡的例如方式
-- your test data
with data(val) as
(select 'Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4' from dual),
-- split by ,
cols as
(select regexp_substr(str, '[^,]+', 1, level) val
from (select val as str from data)
connect by regexp_substr((select val as str from data),
'[^,]+',
1,
level) is not null),
-- split by :
hdr_and_cols as
(select substr(val, 1, instr(val, ':') - 1) as hdr,
substr(val, instr(val, ':') + 1) as val
from cols),
-- split by |
hdr_lvl_vals as
(select distinct x.hdr,
level as entry,
regexp_substr(x.val, '[^|]+', 1, level) as val
from hdr_and_cols x
connect by regexp_substr(x.val, '[^|]+', 1, level) is not null)
-- format output
select w.val as width, h.val as heigth, l.val as length
from (select entry, val from hdr_lvl_vals where hdr = 'Width') w,
(select entry, val from hdr_lvl_vals where hdr = 'Height') h,
(select entry, val from hdr_lvl_vals where hdr = 'Length') l,
(select level as entry
from dual
connect by level <= (select max(entry) from hdr_lvl_vals)) r
where r.entry = w.entry
and r.entry = h.entry
and r.entry = l.entry;
輸出：
WIDTH HEIGTH LENGTH
--------------------
10 25 35
7 5 6
20 6 3
45 45 4
您可以使用集合和樞軸做到這一點：
甲骨文設置：
小助手功能：
CREATE TYPE stringlist IS TABLE OF VARCHAR2(4000);
/
CREATE FUNCTION split_String(
i_str IN VARCHAR2,
i_delim IN VARCHAR2 DEFAULT ','
) RETURN stringlist DETERMINISTIC
AS
p_result stringlist := stringlist();
p_start NUMBER(5) := 1;
p_end NUMBER(5);
c_len CONSTANT NUMBER(5) := LENGTH(i_str);
c_ld CONSTANT NUMBER(5) := LENGTH(i_delim);
BEGIN
IF c_len > 0 THEN
p_end := INSTR(i_str, i_delim, p_start);
WHILE p_end > 0 LOOP
p_result.EXTEND;
p_result(p_result.COUNT) := SUBSTR(i_str, p_start, p_end - p_start);
p_start := p_end + c_ld;
p_end := INSTR(i_str, i_delim, p_start);
END LOOP;
IF p_start <= c_len + 1 THEN
p_result.EXTEND;
p_result(p_result.COUNT) := SUBSTR(i_str, p_start, c_len - p_start + 1);
END IF;
END IF;
RETURN p_result;
END;
/
查詢：
WITH Data (value) AS (
SELECT 'Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4' FROM DUAL
)
SELECT *
FROM (
SELECT REGEXP_SUBSTR(c.COLUMN_VALUE, '^(.+?):(.+?)$', 1, 1, NULL, 1) AS name,
TO_NUMBER(r.COLUMN_VALUE) AS data,
ROW_NUMBER() OVER (PARTITION BY d.value, c.COLUMN_VALUE
ORDER BY ROWNUM
) AS idx
FROM data d,
TABLE(split_String(d.value, ',')) c,
TABLE(split_String(
REGEXP_SUBSTR(c.COLUMN_VALUE, '^(.+?):(.+?)$', 1, 1, NULL, 2),
'|'
)) r
) PIVOT (
MAX(data) FOR name IN ('Width' AS Width, 'Height' AS Height, 'Length' AS Length)
)
ORDER BY idx;
（注：只有一個，你需要指定列名線）
輸出：
IDX WIDTH HEIGHT LENGTH
--- ----- ------ ------
1 10 25 35
2 7 5 6
3 20 6 3
4 45 45 4
只是爲了好玩with ora：tokenize
with w as (select 'Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4' s from dual),
t(s) as (select /*+ NO_XML_QUERY_REWRITE */ r from w,
xmltable('ora:tokenize(.,",")'
passing s
columns r varchar2(100) path '.'))
select w.Width, w.Height, w.Length from(
select /*+ NO_XML_QUERY_REWRITE */ dig,rn,regexp_substr(s,'\w+') as gr from t,
xmltable('
for $c at $i in ora:tokenize(.,"\|")
return <r><dig>{$c}</dig><rn>{$i}</rn></r>'
passing regexp_replace(s,'\w+:')
columns
"DIG" varchar2(30) path '/r/dig',
"RN" varchar2(30) path '/r/rn'
))
pivot
(
max(dig)
for gr in('Width' as Width,'Height' as Height,'Length' as Length)
)w
ORDER BY RN
您是否事先知道列的名稱或是否需要從字符串中動態提取它們？ – MT0