如何對一個組中的重複值進行求和（SSRS 2005）

Question

如何對一個組* （SSRS 2005）中的重複值進行求和。 *

例如。 我的查詢返回值如下所示：

CusID Discount Amount 
1  20  1000 
1  20  2000 
1   5  700 
2  15  1500 
2  15  3000 

但是，當我在組頁腳總結優惠金額，我不能得到像下面的總價值。我得到45的CusID 1而不是25。請幫我解決這個問題。謝謝。

CusID Discount Amount 
1  20  1000 
1  20  2000 
1   5  700 
------------------------ 
Total 25  3700 

2  15  1500 
2  15  3000 
------------------------ 
Total 15  4500 

Answer 1

沒有你的實際數據看起來像，我只能提供一個基於你提供的數據的代碼示例。

declare @table table (CustID int, Discount int, Amount int) 


    insert into @table (CustID,Discount,Amount) 
    select 1 as CusID,20 as Discount,1000 as Amount 
    union all 
    select 1,20,2000 
    union all 
    select 1,5,700 
    union all 
    select 2,15,1500 
    union all 
    select 2,15,3000 

    select 
     CustID, 
     sum(Discount) as Discount, 
     sum(Amount) as Amount 
    from 
    (
     select 
      CustID, 
      Discount, 
      SUM(Amount) as Amount 
     from @table 
     group by CustID, Discount 
    ) a 
    group by CustID 

Answer 2

一個輕微簡化到DForcek42的回答通過使用總和（不同X）

declare @table table (CustID int, Discount int, Amount int) 

insert into @table (CustID,Discount,Amount) 
select 1 as CusID,20 as Discount,1000 as Amount 
union all 
select 1,20,2000 
union all 
select 1,5,700 
union all 
select 2,15,1500 
union all 
select 2,15,3000 

select 
    CustID, 
    sum(distinct Discount), 
    SUM(Amount) as Amount 
from @table 
group by CustID