返回列表值與功能

我想寫查詢，並與一個card_nr工作正常。例如：返回列表值與功能

Declare @card_nr as nvarchar(50) 

set @card_nr = '704487442952000472' 

select 
    a.times, b.times 
from 
    (select 
     stat_id, times 
    from info 
    where card_nr = @card_nr) as a 
left outer join 
    (select 
     stat_id, times 
    from info 
    where card_nr = @card_nr) as b on a.stat_id = b.stat_id+1

而且我得到了正確的結果：

2014-02-04 11:20:00.000 NULL 
2014-02-06 09:44:00.000 2014-02-04 11:20:00.000 
2014-02-12 09:59:00.000 2014-02-06 09:44:00.000 
2014-02-13 10:31:00.000 2014-02-12 09:59:00.000 
2014-02-21 09:49:00.000 2014-02-13 10:31:00.000

我想這樣做，每card_nr從表列表。所以，首先我寫的函數：

alter FUNCTION tabletest 
    (@card_nr as nvarchar(50)) 
RETURNS smalldatetime 
AS BEGIN 
    Declare @sqldata as smalldatetime 

    select 
     @sqldata = b.times 
    from 
     (select 
      stat_id, times 
     from info where card_nr = @card_nr) as a 
    left outer join 
     (select 
      stat_id, times 
     from info where card_nr = @card_nr) as b on a.stat_id = b.stat_id + 1 

    RETURN @datas 
END

我試圖選擇我的查詢功能後：

select name, times, dbo.tabletest(card_nr) 
from dbo.info

而且我得到不正確的結果：

User1 2014-02-04 11:20:00.000 2014-02-21 09:49:00 
User1 2014-02-06 09:44:00.000 2014-02-21 09:49:00 
User1 2014-02-12 09:59:00.000 2014-02-21 09:49:00 
User1 2014-02-13 10:31:00.000 2014-02-21 09:49:00 
User1 2014-02-21 09:49:00.000 2014-02-21 09:49:00 
User2 2014-02-14 13:41:00.000 2014-02-28 12:20:00 
User2 2014-02-24 11:46:00.000 2014-02-28 12:20:00 
User2 2014-02-28 12:20:00.000 2014-02-28 12:20:00

我想得到這個：

User1 2014-02-04 11:20:00.000 NULL 
User1 2014-02-06 09:44:00.000 2014-02-04 11:20:00.000 
User1 2014-02-13 10:31:00.000 2014-02-12 09:59:00.000 
User1 2014-02-13 10:31:00.000 2014-02-12 09:59:00.000 
User1 2014-02-21 09:49:00.000 2014-02-13 10:31:00.000 
User2 2014-02-14 13:41:00.000 NULL 
User2 2014-02-24 11:46:00.000 2014-02-14 13:41:00.000 
User2 2014-02-28 12:20:00.000 2014-02-24 11:46:00.000

來源

2014-03-07 Myk Syk

它應該b é可能得到所需的結果只使用表信息：

select name, times, 
(select max(times) from info i2 where i2.times<i1.times and i1.name=i2.name and [email protected]_nr) 
from info i1 
where [email protected]_nr

來源

2014-03-07 08:47:12 Jayvee

我會嘗試它，但如果我想使用的功能。什麼是正確的功能和查詢？ –

我不想使用一個函數，它們（至少是標量）有時可能會變慢。作爲一個經驗法則，如果你可以用「普通」sql做到這一點。 – jean

@jean同意，如果可能，我會避免函數調用 – Jayvee

返回列表值與功能

回答

相關問題