2010-03-22 58 views
0

我的表是這樣的Postgres的,請注意,所有的日子由01開始,只有1項在一個月+一年在一年之內的日期查詢

SELECT * FROM "fis_historico_receita" 
+----+------------+---------------+ 
| id | data  | receita_bruta | 
+----+------------+---------------+ 
| 1 | 2010-02-01 | 100000.0  | 
| 2 | 2010-01-01 | 100000.0  | 
| 3 | 2009-12-01 | 100000.0  | 
| 4 | 2009-11-01 | 100000.0  | 
| 5 | 2009-10-01 | 100000.0  | 
| 6 | 2009-09-01 | 100000.0  | 
| 7 | 2009-08-01 | 100000.0  | 
| 8 | 2009-07-01 | 100000.0  | 
| 9 | 2009-06-01 | 100000.0  | 
| 10 | 2009-05-01 | 100000.0  | 
| 11 | 2009-04-01 | 100000.0  | 
| 12 | 2009-03-01 | 100000.0  | 
| 13 | 2009-02-01 | 100000.0  | 
| 14 | 2009-01-01 | 100000.0  | 
| 15 | 2008-12-01 | 100000.0  | 
+----+------------+---------------+ 

我想要的是找到12個月從現在開始。

我嘗試這樣做:

select * 
from fis_historico_receita 
where data in interval '1 year' 

我真的想使用間隔一個答案,+1去給大家上的Postgres運行

回答

1

試試這個:

select * 
from fis_historico_receita 
where data BETWEEN NOW() - interval '1 year' AND NOW() 
+0

爲了得到12個月我做了:... BETWEEN(NOW() - 間隔'1年' - 間隔'1個月')AND ...仍然接受指向ver是的 – 2010-03-22 20:40:39

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