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我想通過JSON首次製作一個簡單的WCF RESTful。我在下面有我的界面,但是我將調用哪個URL來調用MemberLogon()方法?WCF RESTful服務配置獲取404
我認爲這將是這樣的:
http://localhost:49701/Exchange.svc/?membershipNumber=6519548&blah=abc
但我得到一個404。我有一種感覺是,在我的web.config我的服務configuraiton做。幫幫我!
我的接口和類是:
[ServiceContract]
public interface IExchange
{
[System.ServiceModel.OperationContract(Name = "MemberLogon")]
[WebInvoke(UriTemplate = "/?membershipNumber={membershipNumber}&blah={blah}", Method = "GET", ResponseFormat = WebMessageFormat.Json)]
Member MemberLogon(string membershipNumber, string blah);
}
[System.Runtime.Serialization.DataContract]
public class Member
{
[System.Runtime.Serialization.DataMember]
public string Username { get; set; }
}
配置爲:
<system.serviceModel>
<behaviors>
<serviceBehaviors>
<behavior name="MyNamespace.MyClass.ExchangeBehavior">
<serviceMetadata httpGetEnabled="true" />
<serviceDebug includeExceptionDetailInFaults="false" />
</behavior>
</serviceBehaviors>
</behaviors>
<services>
<service behaviorConfiguration="MyNamespace.MyClass.ExchangeBehavior" name="MyNamespace.MyClass.Exchange">
<endpoint address="" binding="webHttpBinding" contract="MyNamespace.MyClass.IExchange" />
</service>
</services>
我剛剛得到它正確地使用這個網址與你的配置調用:HTTP://本地主機:49701/Exchange.svc/membershipNumber = 6519548&等等= ABC,但我怎麼能指定的方法調用(如調用MemberLogon )? – AshesToAshes 2012-04-08 17:32:22
從頭開始評論 - 你是明星:)我只需要修改UriTemplate。非常感謝。 – AshesToAshes 2012-04-08 17:36:26