此代碼適用於我正在處理的項目;我顯然試圖調用一個字符串。該程序旨在打印來自SQLite數據庫的測驗分數;方法1,這是我遇到的問題,應該給所有學生的正確課程和難度級別的最新記錄。數據庫看起來像這樣;Python:「str」對象不可調用
CREATE TABLE Scores ( [Key] INTEGER, Score INTEGER NOT NULL, PupilName TEXT NOT NULL, Difficulty BOOLEAN NOT NULL, ClassNumber VARCHAR, DateTime DATETIME );
和代碼(與調試的奇數位)這樣的:
import sqlite3
#import collections
print ("Welcome to the Arithmetic Challenge high score table.")
def MainLoop():
DisplayType = input ("Please enter: 1 for highest scores by student in alphabetical order; 2 for highest scores, highest to lowest; 3 for average scores, highest to lowest. ")
Difficulty = input ("Enter difficulty level.")
ClassNumber = input ("Enter class number.") #Input of variables
conn = sqlite3.connect("QuizStorage")
c = conn.cursor()#Connects
c.execute("SELECT * FROM Scores")
PupilsEligible = c.fetchall()#Finds pupils
#count = collections.defaultdict(int) #?
#print (count)
print (PupilsEligible)
DifficultyInt = int(Difficulty)
if DisplayType == "1":
print (DifficultyInt)
c.execute("SELECT * FROM Scores WHERE Difficulty = (?) AND ClassNumber = (?) ORDER BY # DESC LIMIT 1 ORDER BY PupilName"(DifficultyInt, ClassNumber))
data = c.fetchall()
print (data)
elif DisplayType == "2":
c.execute("SELECT * , MAX(Score) FROM Scores WHERE Difficulty = (?) AND ClassNumber = (?) GROUP BY PupilName"(DifficultyInt, ClassNumber))
data = c.fetchall()
print (data)
elif DisplayType == "3":
c.execute("SELECT * , AVG(Score) FROM Scores WHERE Difficulty = (?) AND ClassNumber = (?) GROUP BY PupilName"(DifficultyInt, ClassNumber))
data = c.fetchall()
print (data)
else:
print ("That's not a valid answer.")
for row in c:
print (row)
conn.close()
MainLoop()
MainLoop()
請注意,該代碼具有較早嘗試是天堂」的各種遺物t還沒有被剪掉。對不起,如果這使得它不清楚。 當我嘗試運行它,我得到這個:
Welcome to the Arithmetic Challenge high score table.
Please enter: 1 for highest scores by student in alphabetical order; 2 for highest scores, highest to lowest; 3 for average scores, highest to lowest. 1
Enter difficulty level.2
Enter class number.3
[('Alice Mann',), ('Fred Pratt',), ('John Smith',), ('Karen James',)]
2
Traceback (most recent call last):
File "H:\My Documents\CA 2\ACHighScore 0.5.5.py", line 37, in <module>
MainLoop()
File "H:\My Documents\CA 2\ACHighScore 0.5.5.py", line 19, in MainLoop
c.execute("SELECT * FROM Scores WHERE Difficulty = (?) AND ClassNumber = (?) ORDER BY # DESC LIMIT 1 ORDER BY PupilName"(DifficultyInt, ClassNumber))
TypeError: 'str' object is not callable
我已經看過了其他類似的錯誤,並已離開毫無收穫。這個錯誤信息究竟意味着什麼,以及如何避免?
您有'c.execute(「某個字符串」(數據))''。 Python認爲你正試圖調用一個字符串作爲函數。 – georg 2015-02-11 09:59:45
...在這裏它應該是'c.execute(「一些字符串,其中blah =(?)和foo =(?)」,(x1,x2))'把這些值放在問號位置。你錯過了一個逗號。 – Spacedman 2015-02-11 10:03:41