在define_method中調用super時沒有超類方法

Question

• 爲什麼我會覆蓋以下錯誤talk: super: no superclass method talk (NoMethodError)當我重寫已存在的方法？
• 我該如何解決這個代碼來調用超級方法？

這裏是我使用

class Foo 
    def talk(who, what, where) 
    p "#{who} is #{what} at #{where}" 
    end 
end 

Foo.new.talk("monster", "jumping", "home") 

class Foo 
    define_method(:talk) do |*params| 
    super(*params) 
    end 
end 

Foo.new.talk("monster", "jumping", "home") 

Answer 1

它不工作，因爲你覆蓋#talk示例代碼。試試這個

class Foo 
    def talk(who, what, where) 
    p "#{who} is #{what} at #{where}" 
    end 
end 

Foo.new.talk("monster", "jumping", "home") 

class Bar < Foo 
    define_method(:talk) do |*params| 
    super(*params) 
    end 
end 

Bar.new.talk("monster", "table", "home")