搜索模式和使新線與它

Question

輸入：

2:this is a sentence 221j: 54: this another sentence: 4245: again a sentence 3:the last sentence 

輸出

this is a sentence 221j: 
this another sentence: 
again a sentence 
the last sentence 

的snipet應搜索由以下1或2或3個數字 '：'。把所有的'：'全部放在下一個模式之後，並且用新的模式。

Answer 1

能否請您嘗試以下的awk（在GNU AWK測試）太讓我知道，如果這可以幫助你，也該是在提供樣品測試INPUT_FILE只。

awk -v RS='[0-9]+:' 'NF{gsub(/^ |\n/,"");print}' Input_file 

輸出如下。

this is a sentence 221j: 
this another sentence: 
again a sentence 
the last sentence 

說明：

awk -v RS='[0-9]+:' ' ##Setting Record Separator as all the digits together with colon. 
NF{     ##Then checking if line is NOT blank by checking NF(number of fields) are NOT null, if yes then do following. 
gsub(/^ |\n/,""); ##Globally substituting starting space and new line with NULL in current line. 
print    ##printing the current line. 
} 
' Input_file  ##Mentioning the Input_file here. 

Answer 2

AWK溶液：

awk -F'[0-9]+:[[:space:]]*' '{for(i=1;i<=NF;i++) if($i) print $i}' inputfile 

• -F'[0-9]+:[[:space:]]*' - 複合字段分隔

---

輸出：

this is a sentence 221j: 
this another sentence: 
again a sentence 
the last sentence 

Answer 3

這確實你說什麼你想（更換1，2，或3位數字:）：

$ awk '{sub(/[0-9]{1,3}: */,""); gsub(/ *[0-9]{1,3}: */,ORS)}1' file 
this is a sentence 221j: 
this another sentence: 4 
again a sentence 
the last sentence 

如果你真正想要的是更換任何整數，其後:你的樣品輸入/輸出指示那麼這會是：

$ awk '{sub(/[0-9]+: */,""); gsub(/ *[0-9]+: */,ORS)}1' file 
this is a sentence 221j: 
this another sentence: 
again a sentence 
the last sentence