使用Java Pattern和Matcher搜索模式，包括標點符號，如斜線

Question

我有一個這樣的字符串：1/80% of all goods sold for $44 million dollars or more/90/55 所以基本上我想有模式的字符串：

「一定數量」「斜槓「‘一些文本與任何標點符號，包括斜槓’，‘斜線’，‘一些數量’，‘斜線’，‘一定數量的’

我不能只用在向前的StringTokenizer和記號化斜槓，因爲我的文字塊可能有正斜槓。我對在java中使用模式和匹配器很陌生。有關我如何做到這一點的任何線索？或者可能有用的教程？提前致謝！根據需要

^\d+/.*/\d+/\d+$ 

添加捕獲組：

Answer 1

也許這會工作作爲一個正則表達式。只要文本不包含換行符，這應該工作。

Answer 2

這個正則表達式應該這樣做：

^(\d+)\/(.*?)\/(\d+)\/(\d+)$ 

演示：http://www.rubular.com/r/ZIhe8iE0L0

Answer 3

你正在尋找＃/＃<文本> /＃/＃

下面是一些代碼應工作：

String toScan = "Did you know that 1/80 of all goods sold for $44 million or more/90/55? It's cool, because 1/5 of all people can type /1/2 like that."; 
    String regexp = "[0-9]{1,}/[0-9]{1,}.{1,}?/[0-9]{1,}/[0-9]{1,}"; 
    Pattern pattern = Pattern.compile(regexp); 
    Matcher m = pattern.matcher(toScan); 
    while(m.find()) 
     System.out.println(m.group()); 

Answer 4

這裏是一個簡單的測試

import java.util.regex.*; 

class RTest 
{ 
public static void main(String[] args) 
{ 
    String test1 = "1/80% of all goods sold for $44 million dollars or more/90/55"; 
    String test2 = "1/80% of all goods sold for $44 /million dollars or more/90/55"; 

    String patternStr = "(.*?)/(.*)/(.*?)/(.*?)$"; 
    Pattern pattern = Pattern.compile(patternStr); 

    System.out.println("Test1..."); 
    // Test 1 
    Matcher matcher = pattern.matcher(test1); 
    boolean matchFound = matcher.find(); 

    if (matchFound) 
    { 
     for (int i = 0; i<=matcher.groupCount(); i++) 
     { 
      System.out.println(matcher.group(i)); 
     } 
    } 

    System.out.println("Test2..."); 
    // Test 2 
    matcher = pattern.matcher(test2); 
    matchFound = matcher.find(); 

    if (matchFound) 
    { 
     for (int i = 0; i<=matcher.groupCount(); i++) 
     { 
      System.out.println(matcher.group(i)); 
     } 
    }  
} 

}