爆炸然後選擇正確的電子郵件？

Question

我有一個字符串，它看起來像這樣：

email@domain1.com | email@domain5.com

我只需要電子郵件匹配 'domain5'。

$domain_needle = 'domain5.com'; 
$employer_email = 'email@domain1.com|email@domain5.com'; 
$employer_email = explode('|', $employer_email); 

我該如何選擇具有domain5的數組成員？

使用substr_count（）？

Answer 1

$domain_needle = 'domain5.com'; 
$employer_email = 'email@domain1.com|email@domain5.com'; 
$employer_email = explode('|', $employer_email); 

foreach($employer_email as $email){ 
    if(strpos($email, $domain_needle) !== false){ 
     $employer_email = $email; 
     break; 
    } 
} 

echo $employer_email; 

Answer 2

你可以使用preg_grep：

$result = preg_grep("/$domain_needle/", $employer_email); 

實施例，與array_shift從返回的數組中提取第一值：

$domain_needle = 'domain5.com'; 
$employer_email = 'email@domain1.com|email@domain5.com'; 
$employer_email = explode('|', $employer_email); 
print array_shift(preg_grep("/$domain_needle/", $employer_email)); 

輸出：

email@domain5.com