迭代通過使用循環

代碼的全部對象和方法的列表可以在這篇文章的底部找到，但真正令我擔憂的是隻是一部分，迭代通過使用循環

for(zed = 0; zed<photoes.size(); zed++) { 
totesPrice += photoes<zed>.getCost(); 
totesSize += photoes<zed>.getMegabytes(); 
totesSpeed = photoes<zed>.getSpeed(); 
}

理想的totesPrice，totesSize ，而totesSpeed將是存儲在photoes list數組中的對象的get方法的總和。

// Import classes for class 
import java.util.Arrays; 
import java.util.List; 
import javax.swing.*; 
import java.awt.event.*; 
import java.text.DecimalFormat; 
import java.util.ArrayList; 

public class DigitalMain 
{ 
    public static void main(String args[]) 
    { 
    String cont = "Y"; 
    String heightString,width,bitpsString = ""; 
    String widthString = ""; 
    int zed; 
    double bitps,pHS,pWS = 0.0; 
    double totesSpeed = 0.0; 
    double totesPrice = 0.0; 
    double totesSize = 0.0; 
    DecimalFormat wholeDigits = new DecimalFormat("0"); 
    DecimalFormat dec = new DecimalFormat("0.00"); 

    List<DigitalPhoto> photoes = new ArrayList<DigitalPhoto>(); 
    do 
    { 
    DigitalPhoto photo = new DigitalPhoto(); 
    heightString = JOptionPane.showInputDialog("Please enter height"); 
    pHS = Double.parseDouble(heightString); 
    photo.setHeight(pHS); 
    widthString = JOptionPane.showInputDialog("Please enter width"); 
    pWS = Double.parseDouble(widthString); 
    photo.setWidth(pWS); 
    JOptionPane.showMessageDialog(null, "Height: " + photo.getHeight() + "\nWidth: " + photo.getWidth() + "\nResolution: " + photo.getResolution() + " DPI\nCompression Ratio: " + photo.getCompression() + "\nRequired Storage: " + dec.format(photo.getKilo()) + " Kilobytes.\nPrice of Scanned Photo: $" + dec.format(photo.getCost()) + " dollars."); 
    do 
    { 
    bitpsString = JOptionPane.showInputDialog("Please enter your internet connection speed in BITS not BYTES please."); 
    bitps = Double.parseDouble(bitpsString); 
    } while (bitps < 0 && bitps > 99999999); 
    photo.setSpeed(bitps); 

    for(zed = 0; zed<photoes.size(); zed++) { 
    totesPrice += photoes<zed>.getCost(); 
    totesSize += photoes<zed>.getMegabytes(); 
    totesSpeed = photoes<zed>.getSpeed(); 
    } 
    cont = JOptionPane.showInputDialog("\nType \'Y\' to try again or anything but \'Y\' to use values."); 
    photoes.add(photo); 
    } while (cont.equalsIgnoreCase("Y")); 





    double seconds = transferTime(totesSize, totesSpeed); 
    double minutes = seconds/60; 
    double realsec = seconds % 60; 

    JOptionPane.showMessageDialog(null, "You will be paying: " + totesPrice + "\nRequired Storage is: " + totesSize + "Required time for transfer is: " + wholeDigits.format(minutes) + " minutes, and " + wholeDigits.format(realsec) + " seconds."); 

    } 

    public static double transferTime(double totalStorage, double netSpeed) { 
    double bits, seconds; 
    bits = (totalStorage * 8); 
    seconds = (bits/netSpeed); 
    return seconds; 
    }; 
}

來源

2012-04-30 user1251814

問題是什麼？ – Paaske

for(zed = 0; zed<photoes.size(); zed++) 
{ 
    totesPrice += photoes.get(zed).getCost(); 
    totesSize += photoes.get(zed).getMegabytes(); 
    totesSpeed = photoes.get(zed).getSpeed(); 
}

試試這個。

來源

2012-04-30 07:05:13

我覺得你有你的仿製藥.. for:each
ü可以試試這個...

for (DigitalPhoto digitalPhoto : photoes) { 
     totesPrice += digitalPhoto.getCost(); 
     totesSize += digitalPhoto.getMegabytes(); 
     totesSpeed = digitalPhoto.getSpeed(); 
    }

來源

2012-04-30 07:07:37

plz如果你投下了票，請發表評論...謝謝 –

你可以使用，而不是一個Iterator：

Iterator it = photoes.iterator(); 
    while(it.hasNext()) 
    { 
    DigitalPhoto temp = it.next(); 
    totesPrice += temp.getCost(); 
    totesSize += temp.getMegabytes(); 
    totesSpeed = temp.getSpeed(); 
    }

來源

2012-04-30 08:38:14

迭代通過使用循環

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