如何拔出從返回JSON字符串的某些數據？

所以我在JavaScript中，需要一個用戶的照片，然後發送它關閉面部識別API的應用程序，它返回一個JSON值，然後我有轉換爲字符串。但我只有兩個返回到我的項目是important.I要拔出這兩個（UID和信心），並將它們設置爲變量;我不完全知道該怎麼做。下面是什麼是返回一個例子：如何拔出從返回JSON字符串的某些數據？

{"photos":[{"url":"http://api.skybiometry.com/fc/images/get?id=bmN2X3hybD0wMTk5c29ub3I0MXE0bjN…RyMTQzJmVxPTE1ODkmY3ZxPTY5MjcxMzEyMTI3cTImZ3Z6cmZnbnpjPTIwMTMwNDE0MTgxNjI5","pid":"[email protected]_69271312127d2","width":380,"height":300,"tags":[{"tid":"[email protected]_69271312127d2_51.05_45.67_0_1","recognizable":true,"threshold":20,"uids":[{"uid":"[email protected]","confidence":100}],"confirmed":false,"manual":false,"width":20,"height":25.33,"center":{"x":51.05,"y":45.67},"eye_left":{"x":56.32,"y":39.67},"eye_right":{"x":46.32,"y":40},"mouth_center":{"x":48.68,"y":55.67},"nose":{"x":50.79,"y":47},"yaw":0,"roll":1,"pitch":0,"attributes":{"face":{"value":"true","confidence":60}}}]}],"status":"success","usage":{"used":5,"remaining":95,"limit":100,"reset_time_text":"Sun, 14 April 2013 18:20:53 +0000","reset_time":1365963653}}

下面是代碼我目前使用的是現在返回整個字符串：

.done(function (result) { 
    alert("Received response.."); 
    var resultObject = JSON.stringify(result); 
    alert(resultObject); 
});

任何幫助，不勝感激！

來源

2013-04-14 user2266621

http://api.jquery.com/jQuery.getJSON/已讀 – smerny

JSON.parse（）來未JSON.stringify（） – monkeyinsight

resultObject [ 'UID']和resultObject [ '信心']？ – NINCOMPOOP

.done(function (result) { 
    if(result != null) { 
     var uids = result.photos[0].tags[0].uids[0]; 
     var uid = uids.uid; 
     var confidence = uids.confidence; 

    } });

來源

2013-04-14 18:50:48 marko

第三行應該是'變種的uid = result.photos [0] .tags添加[0] .uids [0];'。 – brezanac

所以jsfiddle說我應該使用！==比較null，所以繼承人編輯的代碼，我有：.done（函數（結果）{ 如果（結果！== null）{var 0ids = result.photos [0 ] .tags添加[0] .uids [0]; 變種UID = uids.uid; 變種信心= uids.confidence; 警報（UID）; }}）; – user2266621

，並在控制檯中給出錯誤：Uncaught TypeError：無法讀取未定義的屬性'uids' – user2266621

如何拔出從返回JSON字符串的某些數據？

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