在javascript中排列天數

Question

我有一個數組。該數組可以包含1到7個唯一的日期名稱字符串。從星期一到星期日，星期幾的名字將是順序的。 - 如：

[「星期二」，「星期四」，「太陽報」]

我想，這樣的順序將與今天開始使用JavaScript來排序該數組。

即：假如今天是星期五，然後排序數組應該是

[「太陽報」，「星期二」，「星期四」]

如果今天是星期四，則排序後的數組應該

[ 「星期四」， 「太陽報」， 「星期二」]

燦有人幫忙嗎？

Answer 1

function sort_days(days) { 

要獲得今天的星期幾，請使用new Date().getDay()。這假定Sunday = 0, Monday = 1, ..., Saturday = 6。

var day_of_week = new Date().getDay(); 

要生成的一週中各天的列表，然後切片名稱的列表：

var list = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"]; 
    var sorted_list = list.slice(day_of_week).concat(list.slice(0,day_of_week)); 

（今天是星期五，所以sorted_list是['Fri','Sat','Sun','Mon','Tue','Wed','Thu']）

最後，排序，使用indexOf：

return days.sort(function(a,b) { return sorted_list.indexOf(a) > sorted_list.indexOf(b); }); 
} 

全部放在一起：

function sort_days(days) { 
    var day_of_week = new Date().getDay(); 
    var list = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"]; 
    var sorted_list = list.slice(day_of_week).concat(list.slice(0,day_of_week)); 
    return days.sort(function(a,b) { return sorted_list.indexOf(a) > sorted_list.indexOf(b); }); 
} 

Answer 2

這是我想出了一個功能：

function sortDays(days) { 
    var daysOfWeek = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"]; 
    var today = new Date().getDay(); 
    for (var i=0;i<today;i++) daysOfWeek.push(daysOfWeek.shift()); 
    return daysOfWeek.filter(function(d) { return days.indexOf(d) >= 0; }); 
} 

的總體思路是：從開始到結束以關閉今天是什麼日子轉動元件重新安排一週的日子。然後，您使用該順序重新排列輸入數組以匹配。我只是根據輸入數組的內容過濾了daysOfWeek數組，而不是實際排序。

我不確定Array.filter支持的程度如何，所以您可能希望將其更改爲泛型for循環，取決於您想要支持的瀏覽器。

Here's a jsfiddle你也可以在那裏玩。

或者，你可以使用內置的Array.sort方法如下類似的策略：

var daysOfWeek = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"]; 

{ 
    var today = new Date().getDay(); 
    for (var i=0;i<today;i++) daysOfWeek.push(daysOfWeek.shift()); 
} 

function daysOfWeekSorter(x,y) { 
    return daysOfWeek.indexOf(x)-daysOfWeek.indexOf(y); 
} 

var myDays = ["Tue", "Thu", "Sun"]; 
myDays.sort(daysOfWeekSorter); 

而且here's another fiddle一起玩。

Answer 3

以防萬一，我們曾經設法獲得或失去了一天，我已經建立了礦不需要硬編碼的一日清單:)這裏的希望有一天，我們得到了週六和週日之間的額外24小時！

function anyDayNow(dys) { 
    var ret = [], cur = new Date(), today = cur.getUTCDay(), txt; 
    do { 
    txt = cur.toUTCString().split(',')[0]; 
    dys.indexOf(txt)!=-1 && ret.push(txt); 
    cur.setUTCDate(cur.getUTCDate() + 1); 
    } while (cur.getUTCDay() != today); 
    return ret; 
} 

console.log(anyDayNow(["Tue", "Thu", "Sun"])); 

Answer 4

function sortDaysByToday(ds){ 
    var days = {Sun: 0, Mon: 1, Tue: 2, Wed: 3, Thu: 4, Fri: 5, Sat: 6}, 
     today = new Date().getDay() 

    return ds.sort(function(a,b){ 
    return (days[a] < today ? days[a] + 7 : days[a]) 
     - (days[b] < today ? days[b] + 7 : days[b]) 
    }) 
} 

Answer 5

這裏有一個簡單的方法只使用的indexOf，數組的拼接濾波器和CONCAT功能，無需循環：

function sortMyArray(toSort) { 
    var today = new Date().toUTCString().substr(0, 3), //get today as 3 letter string 
     list = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"], // days list 
     before = list.splice(0, list.indexOf(today)); // splice what is before today in the list 

    list = list.concat(before); // concat the list with what was spliced 

    return list.filter(function (item) { return toSort.indexOf(item) !== -1}); // return the sorted list with only the asked days 
} 

使用

console.log(sortMyArray(["Tue", "Thu", "Sun"])); 

Answer 6

const days = ["Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"]; 

const sortDays = function (a, b) { 
    a = days.indexOf(a); 
    b = days.indexOf(b); 
    return a < b ? 0 : 1; 
}; 

const myArrayOfDays = ["Tuesday", "Saturday", "Monday", "Thursday"].sort(sortDays); 
// returns ["Monday", "Tuesday", "Thursday", "Saturday"];