我有8個表在我的數據庫,我需要在他們的一個查詢所有必要的數據。 如果不使用where
聲明,我的查詢工作,但是當我使用我的查詢LIKE
和OR LIKE
,該where
語句無法正常工作在我的mysql查詢不正確的工作
我原來的查詢是:
SELECT `mhr_patients`.`id`,
`mhr_patients`.`fullName`,
`mhr_patients`.`nationalCode`,
`mhr_patients`.`age`,
`mhr_patients`.`firstGCS`,
`mhr_patients`.`fileNumber`,
`mhr_patients`.`isUnKnown`,
`mhr_patients`.`docDetail`,
`mhr_patients`.`presentation`,
`mhr_patients`.`appRegisterTime`,
`mhr_patients`.`inspectorRegisterTime`,
`mhr_patients`.`patientStatusDetail`,
`mhr_patients`.`patientDetail`,
`mhr_patients`.`status`,
`docT`.`text` AS docText,
`tolOp`.`name` AS tolOpName,
`tolOp`.`color` AS tolOpColor,
`tolOp`.`res1` AS tolOpTextColor,
`pLog`.`breathing`,
`pLog`.`bodyMovement`,
`pLog`.`faceMovement`,
`pLog`.`gag`,
`pLog`.`cough`,
`pLog`.`cornea`,
`pLog`.`pupil`,
`pLog`.`dollEye`,
`pLog`.`secondGCS`,
`pLog`.`sedation`,
`pLog`.`inspector`,
`pLog`.`status` As pLogStatus,
`pLog`.`section`,
`pLog`.`id` AS pLogId,
`pLog`.`typeOfSection`,
`pLog`.`lastUpdateTime`,
`pLog`.`isTransfer`,
`pLog`.`opu`,
`hos`.`name` AS hosName,
`mhr_opu`.`name` AS opuName,
`mhr_opu`.`id` AS opuId,
`mhr_states`.`name` AS cityName,
`mhr_inspectors`.`name` AS insName
FROM (`mhr_patients`)
JOIN `mhr_doc` AS docT ON `docT`.`id` = `mhr_patients`.`doc`
JOIN `mhr_tol_options` AS tolOp ON `tolOp`.`id` = `mhr_patients`.`patientStatus`
JOIN `mhr_patients_log` AS pLog ON `pLog`.`pId` = `mhr_patients`.`id` AND pLog.id = (SELECT MAX(mhr_patients_log.id) FROM mhr_patients_log WHERE mhr_patients_log.pId = mhr_patients.id)
JOIN `mhr_hospitals` AS hos ON `hos`.`id` = `pLog`.`hospital`
JOIN `mhr_opu` ON `mhr_opu`.`id` = `pLog`.`opu`
JOIN `mhr_states` ON `mhr_states`.`id` = `pLog`.`city`
JOIN `mhr_inspectors` ON `mhr_inspectors`.`id` = `pLog`.`inspector`
WHERE
`mhr_patients`.`status` = 5
GROUP BY `pLog`.`pId`
ORDER BY `mhr_patients`.`inspectorRegisterTime` asc
LIMIT 30
當我使用上面的查詢,結果是正確的,當我改變mhr_patients
。 status
,返回不同的結果, 但是當我使用以下查詢mhr_patients
。 status
不起作用,無論參數如何,都會給出一個結果
SELECT `mhr_patients`.`id`,
`mhr_patients`.`fullName`,
`mhr_patients`.`nationalCode`,
`mhr_patients`.`age`,
`mhr_patients`.`firstGCS`,
`mhr_patients`.`fileNumber`,
`mhr_patients`.`isUnKnown`,
`mhr_patients`.`docDetail`,
`mhr_patients`.`presentation`,
`mhr_patients`.`appRegisterTime`,
`mhr_patients`.`inspectorRegisterTime`,
`mhr_patients`.`patientStatusDetail`,
`mhr_patients`.`patientDetail`,
`mhr_patients`.`status`,
`docT`.`text` AS docText,
`tolOp`.`name` AS tolOpName,
`tolOp`.`color` AS tolOpColor,
`tolOp`.`res1` AS tolOpTextColor,
`pLog`.`breathing`,
`pLog`.`bodyMovement`,
`pLog`.`faceMovement`,
`pLog`.`gag`,
`pLog`.`cough`,
`pLog`.`cornea`,
`pLog`.`pupil`,
`pLog`.`dollEye`,
`pLog`.`secondGCS`,
`pLog`.`sedation`,
`pLog`.`inspector`,
`pLog`.`status` As pLogStatus,
`pLog`.`section`,
`pLog`.`id` AS pLogId,
`pLog`.`typeOfSection`,
`pLog`.`lastUpdateTime`,
`pLog`.`isTransfer`,
`pLog`.`opu`,
`hos`.`name` AS hosName,
`mhr_opu`.`name` AS opuName,
`mhr_opu`.`id` AS opuId,
`mhr_states`.`name` AS cityName,
`mhr_inspectors`.`name` AS insName
FROM (`mhr_patients`)
JOIN `mhr_doc` AS docT ON `docT`.`id` = `mhr_patients`.`doc`
JOIN `mhr_tol_options` AS tolOp ON `tolOp`.`id` = `mhr_patients`.`patientStatus`
JOIN `mhr_patients_log` AS pLog ON `pLog`.`pId` = `mhr_patients`.`id` AND pLog.id = (SELECT MAX(mhr_patients_log.id) FROM mhr_patients_log WHERE mhr_patients_log.pId = mhr_patients.id)
JOIN `mhr_hospitals` AS hos ON `hos`.`id` = `pLog`.`hospital`
JOIN `mhr_opu` ON `mhr_opu`.`id` = `pLog`.`opu`
JOIN `mhr_states` ON `mhr_states`.`id` = `pLog`.`city`
JOIN `mhr_inspectors` ON `mhr_inspectors`.`id` = `pLog`.`inspector`
WHERE
`mhr_patients`.`status` = 5
AND `mhr_patients`.`fullName` LIKE '%aaa%'
OR `mhr_patients`.`nationalCode` LIKE '%aaa%'
OR `mhr_patients`.`fileNumber` LIKE '%aaa%'
OR `mhr_patients`.`age` LIKE 'aaa'
OR `mhr_patients`.`firstGCS` LIKE 'aaa'
OR `mhr_patients`.`patientDetail` LIKE '%aaa%'
GROUP BY `pLog`.`pId`
ORDER BY `mhr_patients`.`inspectorRegisterTime` asc
LIMIT 30
問題是什麼?
它的工作,謝謝...這不是我的想法 但一個小問題,我使用codeigniter和像我使用$ this-> db-> like();從活躍的記錄,所以我如何添加(&)到我的查詢? – mhrezaei
對不起,我不知道codeiginiter。這是一個不同的問題。如果它解決了您的問題,請不要忘記將其標記爲答案。 – Robbert