表創建失敗：（1064）您的SQL語法中有錯誤

Question

我的代碼有什麼問題？

$query = "CREATE TABLE IF NOT EXISTS 'data_table' (
    'id' INT UNSIGNED NOT NULL AUTO_INCREMENT, 
    'name' VARCHAR(255) NOT NULL, 
    'active' TINYINT NOT NULL DEFAULT '1', 
    'create_date' TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, 
    'income' INT DEFAULT NULL, 
    PRIMARY KEY ('id') 
    ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=1;"; 

$createTable = mysqli_query($connect, $query); 

Answer 1

嘗試：

$query = "CREATE TABLE IF NOT EXISTS `data_table` (
    `id` INT UNSIGNED NOT NULL AUTO_INCREMENT, 
    `name` VARCHAR(255) NOT NULL, 
    `active` TINYINT NOT NULL DEFAULT 1, 
    `create_date` TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, 
    `income` INT DEFAULT NULL, 
    PRIMARY KEY (`id`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=1;"; 

注意，單引號替換爲反引號

Answer 2

你並不需要爲表和列名的單引號嘗試沒有說：你可以使用" or backticks代替。

CREATE TABLE IF NOT EXISTS data_table(
id INT UNSIGNED NOT NULL AUTO_INCREMENT , 
name VARCHAR(255) NOT NULL , 
active TINYINT NOT NULL DEFAULT '1', 
create_date TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP , 
income INT DEFAULT NULL , 
PRIMARY KEY (id) 
) ENGINE = MYISAM DEFAULT CHARSET = utf8 AUTO_INCREMENT =1