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當您嘗試運行查詢並查看錯誤#1064時 - 您的SQL語法中有錯誤;檢查對應於您MariaDB的服務器版本在線路附近使用「」正確的語法5告訴我如何解決#1064 - 您的SQL中有錯誤
CREATE FUNCTION CreateGroup(GroupName VARCHAR(50), GroupIcon TEXT, GroupDescription VARCHAR(130), GroupCreator INT)
RETURNS int(11)
DETERMINISTIC
BEGIN
DECLARE groupID INT;
INSERT INTO groups (name, icon, description) VALUES (GroupName, GroupIcon, GroupDescription);
SET groupID = LAST_INSERT_ID();
INSERT INTO group_members VALUES (groupID, GroupCreator);
RETURN groupID;
END;
CREATE FUNCTION AddMessage(r VARCHAR(255), s INT, t INT, m VARCHAR(255), creation DATETIME)
RETURNS int(11)
DETERMINISTIC
BEGIN
DECLARE lastID INT;
DECLARE receiver INT;
SELECT id INTO receiver from users WHERE username=r;
INSERT INTO messages (receiver_id, sender_id, msg_type, message, created_At) values(receiver, s, t, m, creation);
SET lastID = LAST_INSERT_ID();
INSERT INTO messages_receipt (message_id, user_id, is_delivered) VALUES (lastID, receiver, 0);
RETURN lastID;
END;
CREATE FUNCTION AddGroupMessage(gid INT, s INT, t INT, m VARCHAR(255), creation DATETIME)
RETURNS int(11)
DETERMINISTIC
BEGIN
DECLARE lastID INT; DECLARE rowCount INT;
SELECT COUNT(*) INTO rowCount FROM group_members WHERE user_id = s AND group_id = gid;
IF rowCount = 1 THEN
INSERT INTO group_messages (group_id, user_id, msg_type, message, created_at) VALUES (gid, s, t, m, creation);
SET lastID = LAST_INSERT_ID();
INSERT INTO group_receipt (message_id, user_id, is_delivered) SELECT gm.message_id, gmembers.user_id, 0 FROM
group_messages gm LEFT JOIN group_members gmembers ON gmembers.group_id = gm.group_id WHERE gm.group_id = gid AND gm.message_id = lastID AND NOT gmembers.user_id = s;
RETURN lastID;
ELSE
return 0;
END IF;
END;
CREATE DEFINER = 'inikspbh_weeki'@'localhost'
FUNCTION AddGroupMember(GroupID INT, MemberName VARCHAR(255), Username INT)
RETURNS int(11)
BEGIN
INSERT INTO group_members VALUES (GroupID, MemberName);
RETURN 1;
END;
關於引用varchar數據類型術語的單引號使用php術語 –
您是否更改了DELIMITER? – Strawberry