使用foreach循環查找變量POST數據

Question

爲什麼不能正常工作？

// I'm sending this data: $_POST['amount_1'] = '3'; 
$val = '1'; // This is coming from a foreach loop, but I'm specifying here for simplicity 
echo $_POST['amount_'.$val]; // Returns null 
echo $_POST['amount_1']; // Returns 3 

嘗試獲取POST值時不允許使用變量嗎？

編輯：爲每個請求發佈更多代碼。

$outgoing = array(); 

foreach($_POST as $key => $val): 
    if(strpos($key,'_number_')){ // Matching 'item_number_' would return false because of 0-indexing 
     $item_id = $val; 
     $test = str_replace('item_number_',$key); // Realized when pasting this that I didn't have a $replacement defined. 
     $quantity = $_POST['quantity_'.$test]; 

     $name = $_POST['lp-name']; 
     $email = $_POST['lp-email']; 
     $phone = $_POST['lp-phone']; 

    array_push($outgoing,array($test,$item_id,$quantity,$name,$email,$phone)); 
    } 
endforeach; 

$json = json_encode($outgoing); 

現在就開始工作。我沒有在我的str_replace（）中定義的$replacement。

Answer 1

而不是做這個的，你可以在表單元素使用數組表示法：

<form> 
    <input name='amount[]' value='this is first'> 
    <input name='amount[]' value='this is second'> 
    <input name='amount[]' value='this is last'> 
</form> 

提交這份表格，以陣列形式發送數據：

echo $amount[0]; // this is first 
echo $amount[1]; // this is second 
echo $amount[2]; // this is last 

最良好的祝願，

Korvin