ViewController接收ID而不是SQLite查詢中的數據

Question

我有一個數據庫有一個'單詞'表（存儲單詞）的視圖，我想檢索並將數據發送到另一個ViewController，而不是接收實際的詞，我得到id。

這裏是我的代碼：

(void)getListData { 

//tableData = [[NSMutableArray alloc]init]; 
sqlite3_stmt *statement; 
NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES); 
NSString *documentsDirectory = [paths objectAtIndex:0]; 
NSString *path = [documentsDirectory stringByAppendingPathComponent:@"dexternotedb.sqlite"]; 

if (sqlite3_open([path UTF8String], &database) == SQLITE_OK) { 
    WordListViewController *temp = APP_DELEGATE.wordListViewController; 
    NSLog(@"word id %ld",(long)[temp.wordId integerValue]); 

    NSString *sql=[NSString stringWithFormat:@"SELECT * FROM words WHERE word_id=\"%@\"",APP_DELEGATE.wordListViewController.wordId]; 
    const char *read_stmt = [sql UTF8String]; 
    NSLog(@"select query%@",sql); 


    if(sqlite3_prepare_v2(database, read_stmt, -1, &statement, NULL) == SQLITE_OK){ 
     sqlite3_bind_int(statement, 1, [temp.wordId integerValue]); 

     while(sqlite3_step(statement) == SQLITE_ROW) { 
      NSString *word1 = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 0)]; 
      [word addObject:word1]; 
      NSString *meaning1 = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 0)]; 
      [meaning addObject:meaning1]; 

      NSString *sentence1 = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 0)]; 
      [Sentence addObject:sentence1]; 

     } 


    sqlite3_finalize(statement); 
} else { 
      sqlite3_close(database); 
      NSAssert1(0, @"Failed to open database with message '%s'.", sqlite3_errmsg(database)); 

} 

Answer 1

第一：

不要使用「SELECT *」，因爲你真的不知道該列的順序，並且使用的是列索引來訪問它們。

所以，你應該使用真實姓名 「選擇，ID，字......」

二：

你的所有列檢索都指向同一個索引0：

[NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 0)]; 

這就是爲什麼你得到相同的數據（ID），因爲它只有第一個索引。所以將其更改爲正確的索引1，2，3，而且你會得到正確的DATAS ..

使用該SQL（檢查列名是正確的）

SELECT word_id, word, meaning, sentence FROM words WHERE word_id=\"%@\" 

然後你就可以使用正確的索引爲sqlite3_column_text：

NSString *word1 = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 1)]; 
      [word addObject:word1]; 
      NSString *meaning1 = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 2)]; 
      [meaning addObject:meaning1]; 

      NSString *sentence1 = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 3)]; 
      [Sentence addObject:sentence1];