如果PHP中的/ Elseif語句

我們正在嘗試爲變量$day創建if/elseif語句。我們在與這個PHP相關的HTML代碼中定義了變量及其值。我將把PHP部分粘貼到這個頁面。問題是結果頁面只給出「$ day = 1」的響應。有沒有人知道這個代碼會導致這種情況發生的錯誤？我們也嘗試過使用兩個等號，但這使情況變得更糟！如果PHP中的/ Elseif語句

echo "<p>"; 
       if ($day = 1) { 
        echo "Sunday Funday! What COMMITMENT to going out!"; 
       } elseif ($day = 2) { 
        echo "The start of what's sure to be a rough week. Drink away your sorrows."; 
       } elseif ($day = 3) { 
        echo "Epic night! SO many themes at the bars!"; 
       } elseif ($day = 4) { 
        echo "Hump day!! But seriously, what are you doing...? Aren't you too hungover from last night?"; 
       } elseif ($day = 5) { 
        echo "Thirsty Thursday!! It's close enough to the weekend... right?"; 
       } elseif ($day = 6) { 
        echo "It's Friiiiiiday, Friiiiiiiday, Gotta get down on Friiiiiiiiiday!"; 
       } elseif ($day = 7) { 
        echo "It's FRATurday! Go have some fun!"; 

      }

來源

2012-05-06 user1377549

你肯定需要2個等號，因爲= – jmort253

你想用if/else嗎？像這種情況下最好使用開關， – mfadel

你確實需要使用'=='。「變得更糟」是什麼意思？ – trutheality

您正在分配（=）。您需要一個邏輯相等（==）。

if ($day == 1) { 
    echo "Sunday Funday! What COMMITMENT to going out!"; 
}

退房comparison和logical operators。也是switch() statement。

來源

2012-05-06 03:02:32

當您的意思是使用比較==時，您正在使用作業=。

賦值語句，什麼是在右側，所以

if ($day = 1)

相同

if (1)

這緣於these rules相同

if (true)

這應該解釋爲什麼程序的行爲就像它一樣，當然你現在知道如何解決它。但是，如果你使用的switch聲明它甚至會更好：

switch($day) { 
    case 1: 
     echo "Sunday Funday! What COMMITMENT to going out!"; 
     break; 
    case 2: 
     echo "The start of what's sure to be a rough week."; 
     break; 
    // etc etc 
}

來源

2012-05-06 03:02:41 Jon

當我們添加兩個等號時，整個echo語句從結果頁面中消失。 – user1377549

那麼問題顯然不是比較，但'$ day'不等於您測試的任何值。你可以使用'var_dump（$ day）'來查看它實際是什麼。 – Jon

的比較操作是==，而不是=。

也可以嘗試這種查找表的方法，這是在這種情況下，清潔：

$day_msg = array(
    1 => "Sunday Funday! What COMMITMENT to going out!", 
    2 => "The start of what's sure to be a rough week. Drink away your sorrows.", 
    3 => "Epic night! SO many themes at the bars!", 
    4 => "Hump day!! But seriously, what are you doing...? Aren't you too hungover from last night?", 
    5 => "Thirsty Thursday!! It's close enough to the weekend... right?" 
    6 => "It's Friiiiiiday, Friiiiiiiday, Gotta get down on Friiiiiiiiiday!", 
    7 => "It's FRATurday! Go have some fun!" 
); 
echo "<p>"; 
echo $day_msg[$day];

來源

2012-05-06 03:03:04 eepp

你首先想到的是對的，你需要的等號。

來源

2012-05-06 03:03:38

你想所有的條件這樣

  if ($day == 1) { 
       echo "Sunday Funday! What COMMITMENT to going out!"; 
      } elseif ($day == 2) { 
       echo "The start of what's sure to be a rough week. Drink away your sorrows."; 
      } elseif ($day == 3) { 
       echo "Epic night! SO many themes at the bars!"; 
      } elseif ($day == 4) { 
       echo "Hump day!! But seriously, what are you doing...? Aren't you too hungover from last night?"; 
      } elseif ($day == 5) { 
       echo "Thirsty Thursday!! It's close enough to the weekend... right?"; 
      } elseif ($day == 6) { 
       echo "It's Friiiiiiday, Friiiiiiiday, Gotta get down on Friiiiiiiiiday!"; 
      } elseif ($day == 7) { 
       echo "It's FRATurday! Go have some fun!"; 

     }

來源

2012-05-06 03:04:20 mfadel

如果你的條件要檢查一個長長的清單，你通常不會想寫if/else語句的長鏈。而是嘗試switch塊，甚至是array圖：

$map = array(
    1 => "Sunday Funday! What COMMITMENT to going out!", 
    2 => "The start of what's sure to be a rough week. Drink away your sorrows.", 
    3 => "Epic night! SO many themes at the bars!", 
    4 => "...", 
);

至於那麼代碼變得很簡單：

echo $map[ $day ];

（理想情況下，就可以使用isset支票，但對於開發階段PHP是聰明如果輸入值已經被約束/斷言，則不需要）

來源

2012-05-06 03:08:43 mario

+1用於數組映射參考。 –

如果PHP中的/ Elseif語句

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