如何通過實地SQL

Question

數不同羣組我在數據庫中有數據：

nama    tanggal  
ADIESTY.SW  2017-03-01 
ADIESTY.SW  2017-03-01 
ADIESTY.SW  2017-03-02 
ADIESTY.SW  2017-03-02 
ADIESTY.SW  2017-03-03 
ADIESTY.SW  2017-03-03 
ADIESTY.SW  2017-03-05 
ADIESTY.SW  2017-03-05 
ALFRED APDIAN 2017-03-01 
ALFRED APDIAN 2017-03-01 
ALFRED APDIAN 2017-03-02 
ALFRED APDIAN 2017-03-02 
ARI PUTRA  2017-03-01 
ARI PUTRA  2017-03-01 
ARI PUTRA  2017-03-02 
ARI PUTRA  2017-03-02 
ARI PUTRA  2017-03-03 
ARI PUTRA  2017-03-03 

如何通過不同的日期計算。所以我想結果是：

nama   tanggal 
ADIESTY.SW  4 
ALFRED APDIAN  2 
ARI PUTRA   3 

Answer 1

使用此

select nama,count(distinct tanggal) from your_table 
group by nama; 

http://rextester.com/ZOZQK78377

Answer 2

若要獲取數據的查詢應該是

SELECT `name`, COUNT(*) as `count` 
FROM `table` 
GROUP BY `name` 

Answer 3

試試這個：

  select name,count(name) as count from (
    select 'ADIESTY.SW' as Name,'2017-03-01' as date union 
    select 'ADIESTY.SW' as Name,'2017-03-02'as date union 
    select 'ADIESTY.SW' as Name,'2017-03-03'as date union 
    select 'ADIESTY.SW' as Name,'2017-03-05'as date union 
    select 'ALFRED APDIAN'as Name,'2017-03-01'as date union 
    select 'ALFRED APDIAN' as Name,'2017-03-02'as date union 
    select 'ARI PUTRA' as Name, '2017-03-01'as date union 
    select 'ARI PUTRA' as Name,'2017-03-02'as date union 
    select 'ARI PUTRA' as Name, '2017-03-03'as date 
)t 
    group by name 

Answer 4

當你發佈問題指定使用的數據庫的類型（Oracle，MySQL，..）

SELECT name, COUNT(*) 
FROM yourTable 
GROUP BY name