我想從下拉列表中選擇一個動態數據並查看所選項目的詳細信息。使用數據庫中的數據填充下拉列表時,我沒有問題。但是,當我選擇一些項目時,它不顯示細節。下拉列表選擇的項目
在我的表現層,在下拉列表項中選擇:
protected void ddlScheduleList_SelectedIndexChanged(object sender, EventArgs e)
{
string address = ddlScheduleList.SelectedItem.ToString();
Distribution scheduledIndv = new Distribution();
scheduledIndv = packBLL.getDistributionDetail(address);
if (scheduledIndv == null)
{
Console.Out.WriteLine("Null");
}
else
{
tbScheduleDate.Text = scheduledIndv.packingDate.ToString();
tbBeneficiary.Text = scheduledIndv.beneficiary;
}
}
在我的商業邏輯層,我得到選定的地址,並把它傳遞給數據訪問層:
public Distribution getDistributionDetail(string address)
{
Distribution scheduledIndv = new Distribution();
return scheduledIndv.getDistributionDetail(address);
}
在我的數據訪問層中,我已經測試了SQL語句。它給了我我想要的。但它不會顯示在網頁上。
public Distribution getDistributionDetail(string address)
{
Distribution distributionFound = null;
using (var connection = new SqlConnection(FoodBankDB.GetConnectionString())) // get your connection string from the other class here
{
SqlCommand command = new SqlCommand("SELECT d.packingDate, b.name FROM dbo.Distributions d " +
" INNER JOIN dbo.Beneficiaries b ON d.beneficiary = b.id " +
" WHERE b.addressLineOne = '" + address + "'", connection);
connection.Open();
using (var dr = command.ExecuteReader())
{
if (dr.Read())
{
DateTime packingDate = DateTime.Parse(dr["packingDate"].ToString());
string beneficiary = dr["beneficiary"].ToString();
distributionFound = new Distribution(packingDate, beneficiary);
}
}
}
return distributionFound;
}
而我的執行方法,讀者在相互分離的類:
public static string connectionString = Properties.Settings.Default.connectionString;
public static string GetConnectionString()
{
return connectionString;
}
public static SqlDataReader executeReader(string query)
{
SqlDataReader result = null;
System.Diagnostics.Debug.WriteLine("FoodBankDB executeReader: " + query);
SqlConnection connection = new SqlConnection(connectionString);
SqlCommand command = new SqlCommand(query, connection);
connection.Open();
result = command.ExecuteReader();
connection.Close();
return result;
}
我不知道哪裏出了問題。是關於(!IsPostBack)還是?
在此先感謝。
我相信你將需要讓它回來後,以填充它。或者將其綁定到數據庫。 – Jmoreland91
我發現我的錯誤了。我忘了在下拉列表中啓用回帖。謝謝 –
您有一個SQL注入漏洞。 – SLaks