查找記錄這不/的確存在

Question

我需要向他們報告的員工沒有存儲在一個名爲employee_time等表中的考勤卡輸入的時間。

我的問題是要找到誰沒有進入時間說周的人。

我已經使用了NOT IN發現不存在於表中，因此，如果已經輸入記錄不存在任何時候員工ID。這很好。

Select 
    e.userName, 
    et.dateStart, 
    et.dateEnd 

From employee_time et, 
     employee e 
Where 
     e.employee_id NOT IN (Select employee_id from employee_time 
          where et.dateStart = date and 
            et.end_date = date) 
Group by 
     e.userName, 
     et.startDate, 
     et.endDate 

的問題是應用程序，當一個人導航到員工的時間輸入頁面它創造紀錄的員工，如果員工不進入任何時間，結果是零小時的記錄。但是這個記錄現在存在。因此，不會在上面的查詢可以發現，我已經使用了以下查找其總計記錄= 0

Select 
    e.userName, 
    et.dateStart, 
    et.dateEnd, 
    SUM(et.hoursTotal) AS total 

From employee_time et, 
     employee e 
Where 
     e.employee_id = et.employee_id and 
     et.hours_total = 0 
Group by 
     e.userName, 
     et.startDate, 
     et.endDate 

這也非常實用，但是我需要與他們結婚，但一直不成功的日期。你能幫我嗎？

Answer 1

Select 
    e.userName, 
    et.dateStart, 
    et.dateEnd, 
    SUM(et.hoursTotal) AS total 

From 
     employee e left outer join employee_time et on (e.employee_id = et.employee_id) 
-- Where nvl(et.hours_total,0) = 0 
Group by 
     e.userName, 
     et.startDate, 
     et.endDate 
having SUM(et.hoursTotal) > 0 

如果你不希望有您可以使用作了評論，這應該是相同的

，如果你只想要employee_ids：

select e.empolyee_id 
from employee e left outer join employee_time et on (e.employee_id = et.employee_id) 
Where nvl(et.hours_total,0) = 0; 

Answer 2

一般格式是這樣的：

Select employee_id 
    From employee 
Minus 
Select employee_id 
    From TableExpressionEliminatesOnMissingDates 
Minus 
Select employee_id 
    From TableExpressionEliminatesOnSummarization; 

Answer 3

我會爲這樣寫：

Select e.userName 
From employee e 
Where e.employee_id NOT IN (Select employee_id 
          from employee_time 
          where et.dateStart = $date and 
            et.end_date = $date and 
            et.hoursTotal > 0 
          ); 

您從開始的日期作爲輸入，所以我不明白爲什麼你需要它的輸出也是如此。如果你這樣做，我會去：

Select e.userName, w.* 
From employee e cross join 
    (select distinct et.dateStart, et.end_date 
     from employee_time et 
     where $date between et.dateStart and et.dateEnd 
    ) w 
Where e.employee_id NOT IN (Select et.employee_id 
          from employee_time et 
          where $date between et.dateStart and et.dateEnd and 
            et.hoursTotal > 0 
          ); 

注：在外部查詢。避免GROUP BY是在性能方面的勝利。

Answer 4

以下查詢發現，在employee_time對於給定的開始和結束日期沒有有效的條目中的所有員工：

select * 
from employee 
where employee_id not in 
(
    select employee_id 
    from employee_time 
    where datestart = :date_start 
    and end_date = :date_end 
    and hours_total > 0 
);