從資源文件/內容獲取流

Question

這是從資源文件獲取流的正確方法嗎？

Uri uri = new Uri(fullPath); 

    StorageFile storageFile = 
     await Windows.Storage.StorageFile. 
     GetFileFromApplicationUriAsync(uri); 

    IRandomAccessStreamWithContentType randomAccessStream = 
     await storageFile.OpenReadAsync(); 

    IInputStream resourceStream = (IInputStream) 
     randomAccessStream.GetInputStreamAt(0); 

我所有的其他來源（HTTP和本地存儲）返回一個Stream對象，而且它是痛苦的必須使用一個或另一個的if-else代碼。

我也嘗試過創建一個MemoryStream出來，但我甚至找不到一個方法來獲取字節......請幫助。

uint size = (uint)randomAccessStream.Size; 
    IBuffer buffer = new Windows.Storage.Streams.Buffer(size); 
    await randomAccessStream.ReadAsync(buffer, size, 
     InputStreamOptions.None); 

    Stream stream = new MemoryStream(buffer); // error takes byte[] not IBuffer 

IInputStream.ReadAsync從資源讀取時（）： http://msdn.microsoft.com/en-us/library/windows/apps/windows.storage.streams.iinputstream.readasync.aspx

而Stream.Read（）和Stream.ReadAsync（）是這樣的：

http://msdn.microsoft.com/en-us/library/system.io.stream.read.aspx

和

http://msdn.microsoft.com/en-us/library/hh137813.aspx

謝謝

Answer 1

好的，我發現它！

StorageFile storageFile = 
     await Windows.Storage.StorageFile.GetFileFromApplicationUriAsync(uri); 

    var randomAccessStream = await storageFile.OpenReadAsync(); 
    Stream stream = randomAccessStream.AsStreamForRead(); 

Answer 2

你也可以做到在一個較小的線：

Stream stream = await storageFile.OpenStreamForReadAsync();